小编And*_*ski的帖子

我试图找出为什么我必须throw在main方法中异常,而我有try/ catch块可以处理这些异常？即使我删除了throws IllegalArgumentException,InputMismatchException部分,该程序仍然可以编译并完美地工作.

public static void main(String[] args) throws IllegalArgumentException,InputMismatchException{
    boolean flag = true;
    Scanner in = new Scanner(System.in);
    do{
        try{
            System.out.println("Please enter the number:");
            int n = in.nextInt();
            int sum = range(n);
            System.out.println("sum = " + sum);
            flag = false;
        }
        catch(IllegalArgumentException e){
            System.out.println(e.getMessage());
        }
        catch(InputMismatchException e){
            System.out.println("The number has to be as integer...");
            in.nextLine();
        } 

我有一个看起来像这样的字符串

The#red#studio#502#4

我需要将它分成数组中的3个不同的字符串

s[0] = "The red studio"
s[1] = "502"
s[2] = "4"

问题是第一个应该只有单词而第二个和第三个应该只有数字......

我试图玩这个s.split()方法,但没有运气.

**这是我创建的课程的一部分

    class Student{ 
 private String name;

 private float avGrade;

 private float outstandingGrade = 82.0f;

public Student() {  }

public Student(String Name, float avg) {
    name = Name;
    avGrade = avg;
}

public String getName() {
    return name;
}
public void setName(String Name) {
    name = Name;
}

}

这是其中的主要方法和另一种方法:

    public static void main(String[] args) {
    Student[][] school = CreateStudentMat();
    school[0][0].setName("Student");
}
public static Student[][] CreateStudentMat(){
    Scanner input = new Scanner(System.in);
    System.out.println("Please enter number of classes in school: ");
    int NumClasses …