我总是希望获得数组中元素的确切路径.示例数组:
array(a=>'aaa', 'b'=> array ('bbb1', 'bbb2' => array('bbb3', 'bbb4')));
Run Code Online (Sandbox Code Playgroud)
因此,为了达到'bbb4',我需要经历(b => bbb2 => bbb4).如何在多维数组中获取此路径?
如标题中所述,我遇到了SQL注入错误:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1
我该如何解决?下面提供的是我的PHP代码和HTML代码
PHP:
if($_POST['submit']=='Change')
{
$err = array();
if(!$_POST['password1'] || !$_POST['passwordnew1'])
$err[] = 'All the fields must be filled in!';
if(!count($err))
{
$_POST['password1'] = mysql_real_escape_string($_POST['password1']);
$_POST['passwordnew1'] = mysql_real_escape_string($_POST['passwordnew1']);
$row = mysql_fetch_assoc(mysql_query("SELECT id,username FROM members WHERE username='{$_SESSION['username']}' AND pass='".md5($_POST['password1'])."'"));
if($row['username'])
{
$querynewpass = mysql_query("UPDATE members SET pass='".md5($_POST['passwordnew1'])."' WHERE username='{$_SESSION['username']}'");
$result = mysql_query($querynewpass) …Run Code Online (Sandbox Code Playgroud) 它也发生在PHP中.每当pass1进入提示弹出窗口时,它下方的警报就会像往常一样显示出来.但在那之后,其他警报框也出现了.如何在pass1上停止执行其他警报框?
function download()
{
x=prompt("Enter the download code here.")
if (x=="pass1")
{
alert("This function has been deleted by the administrator. Jeff, get the hell out of here.")
}
if (x=="pass2")
{
alert("I like pie too.")
}
else
{
alert("The code you specified was invalid.")
}
}
Run Code Online (Sandbox Code Playgroud) 我想了解这段代码之间的区别:
(function() {
Run Code Online (Sandbox Code Playgroud)
而这段代码:
$(function() {
Run Code Online (Sandbox Code Playgroud)
第一个示例是否在文档就绪后运行代码,第二个示例是什么?或者仅仅是功能的范围,仅此而已?