我$http在AngularJs中使用,我不确定如何使用返回的promise并处理错误.
我有这个代码:
$http
.get(url)
.success(function(data) {
// Handle data
})
.error(function(data, status) {
// Handle HTTP error
})
.finally(function() {
// Execute logic independent of success/error
})
.catch(function(error) {
// Catch and handle exceptions from success/error/finally functions
});
这是一个很好的方法吗,还是有更简单的方法？
我的网格中有3列的字符串过滤器.这工作正常.在第三列,其dataindex是abc我想修改输入的值.
例如,如果我按0然后它过滤了所有具有0的数据.我想按'否'而不是0来过滤.同样,我想使用"是"而不是1来过滤数据1.
我的代码用于创建过滤器.
this.filters = new Ext.ux.grid.GridFilters({
filters: this.filter,
local: true,
autoReload: false,
});
this.features = [this.filters];
this.plugins = [this.filters];
插入过滤器的代码.
gridEl.filter.push({
type: header.getAttribute("FILTER"),
dataIndex: header.getAttribute("DATAINDEX"),
encode: false,
metaID: header.getAttribute("M"),
});
感谢帮助.
我有以下json对象:
var json = {
"Lofts": "none",
"Maisons": "2",
"HOMES": [{
"home_id": "1",
"price": "925",
"num_of_beds": "2"
}, {
"home_id": "2",
"price": "1425",
"num_of_beds": "4",
}, {
"home_id": "3",
"price": "333",
"num_of_beds": "5",
}]
};
如何过滤此对象并保留在home_id = 2的HOMES属性中？
结果:
var json = {
"Lofts": "none",
"Maisons": "2",
"HOMES": [{
"home_id": "2",
"price": "1425",
"num_of_beds": "4",
}]
};
有什么方法可以循环对象和mantein所有的属性(也是阁楼和maisons)？
谢谢
function foo(str, a) {
eval( str );
console.log( a, b );
}
foo( "var b = 3;", 1 );
这很好用,但是当我们使用let而不是var时,它不起作用.为什么？
嗨,我想在JavaScript中实现观察者模式:
我的index.js:
$(document).ready(function () {
var ironMan = new Movie();
ironMan.setTitle('IronMan');
ironMan.setRating('R');
ironMan.setId(1);
// ironMan.setCast(['Robert Downey Jr.', 'Jeff Bridges', 'Gwyneth Paltrow']);
var terminator = new Movie();
terminator.setTitle('Terminator');
terminator.setRating('P');
terminator.setId(2);
console.log(ironMan.toString());
console.log(terminator.toString());
ironMan.play();
ironMan.stop();
ironMan.download();
ironMan.share('V. Rivas');
console.log(ironMan.getCast()[0]);
});
我的电影:
var title;
var rating;
var id;
var observers;
function Movie() {
observers = new ObserverList();
}
//function Movie (title, rating, id){
// this. title = title;
// this.rating = rating;
// this.id =id;
// observers = new ObserverList();
//} …表单验证我正在使用https://jqueryvalidation.org.我已经通过depends属性实现了自定义验证规则.
以下是验证错误规则:
如果未选中两个价格框,则不会显示错误.
如果选择了一个价格框(两个中的一个),则验证错误将显示用户需要同时选择两个.
如果两者都被选中,那么最大价格值必须大于最低价格.
请在下面找到我的代码:
在我的代码中,每个条件都令人满意,但最后一条规则意味着最高价格总是大于最低价格不起作用.它的检查是正确的,但验证不会触发.
这里是jsfiddle链接
$(document).ready(function() {
$("#form1").validate({
debug: true,
onkeyup: false,
onfocusout: false,
onclick: false,
rules: {
minrange: {
required: {
depends: function() {
var min_range = $("#min-range").find(':selected').val(),
max_range = $("#max-range").find(':selected').val();
if (min_range == "" && max_range == "") {
return false;
} else if (min_range != "" && max_range == "") {
return true;
} else if (min_range == "" && max_range != "") {
return true;
} else if (parseInt(max_range) < …我的Xampp控制面板出现问题.一旦我尝试启动它,它会弹出一条错误消息:
"错误:无法创建文件"C:\ xampp\xampp-control.ini".访问被拒绝.
我安装的版本是xampp-win32-5.6.23.当我尝试启动apache模块时,下面是log respnse:
7:53:14 PM [Apache] Attempting to start Apache app...
7:53:15 PM [Apache] Status change detected: running
7:53:17 PM [Apache] Status change detected: stopped
7:53:17 PM [Apache] Error: Apache shutdown unexpectedly.
7:53:17 PM [Apache] This may be due to a blocked port, missing dependencies,
7:53:17 PM [Apache] improper privileges, a crash, or a shutdown by another method.
7:53:17 PM [Apache] Press the Logs button to view error logs and check
7:53:17 PM [Apache] the Windows Event Viewer …我在codepen中使用以下代码并面临此问题,对于conctact我收到以下错误
为什么它会给出错误的联系而不是名字？
我怎么解决这个问题？
angular.js:13550 ReferenceError: contact is not defined
at new <anonymous> (pen.js:8)
at Object.invoke (angular.js:4665)
at R.instance (angular.js:10115)
at n (angular.js:9033)
at g (angular.js:8397)
at g (angular.js:8400)
at angular.js:8277
at angular.js:1751
at n.$eval (angular.js:17229)
at n.$apply (angular.js:17329)
这是js文件
var app = angular.module("crud", []);
app.controller("ctrl", ['$scope', function($scope) {
$scope.data = [3, 4, 5, 34, 34];
debugger;
$scope.name = name;
$scope.contact = contact;
$scope.obj = {
name: $scope.name,
contact: $scope.contact
};
console.log($scope.obj);
}]);
这是我正在使用的HTML文件.
<body ng-app="crud">
<div ng-controller="ctrl">
<div>
<table>
<tr …我是学习JavaScript概念的新手.想了解原型继承是如何工作的.我的印象是,如果您的类继承了它的父级,并且在两个类的原型中都有相同的命名方法,当您在子实例上调用该方法时,将调用子原型中的方法.
码:
function Animal(name) {
this.name = name;
}
Animal.prototype.printName = function () {
console.log(this.name + ' in animal prototype');
}
function Cat(name) {
Animal.call(this, name);
}
Cat.prototype.printName = function () {
console.log(this.name + ' in cat prototype');
}
Cat.prototype = Object.create(Animal.prototype);
var anm1 = new Animal('mr cupcake');
anm1.printName();
var cat1 = new Cat('cat');
cat1.printName();
在调用cat1.printName()时,我希望它能记录'cat in cat prototype',但它记录了'cat in Animal prototype'.有人可以向我解释一下原因.谢谢.
这是我的Html和JavaScript代码,我想通过函数更改它.
Html:
<div class="container" ng-app="myApp" ng-controller="myController">
<h2>{{title}}</h2>
<ul ng-init="initItems()">
<li ng-repeat="item in items">
<input ng-model="item.name" type="text"/>
<div ng-if="makeVisible == item.id && makeVisible !='' ">
<input ng-model="newname" type="text"/>
<button ng-click="hideme(item.id); rename()" type="button">
<span class="glyphicon glyphicon-ok">
</span>
</button>
<button ng-click="hideme(item.id)" type="button">
<span class="glyphicon glyphicon-remove">
</span>
</button>
</div>
<input ng-click=" showme( item.id)" type="button" value="Rename"/>
</li>
</ul>
</div>
JavaScript:
function item(id, name) {
this.id = id;
this.name = name;
};
angular.module('myApp', []).controller('myController', function($scope) {
$scope.items = [];
$scope.makeVisible = "";
$scope.initItems = …