小编zal*_*hya的帖子

为什么这个节目,

char *s, *p, c;

s = "abc";

printf(" Element 1 pointed to by S is '%c'\n", *s);
printf(" Element 2 pointed to by S is '%c'\n", *s+1);
printf(" Element 3 pointed to by S is '%c'\n", *s+2);
printf(" Element 4 pointed to by S is '%c'\n", *s+3);
printf(" Element 5 pointed to by S is '%c'\n", s[3]);
printf(" Element 4 pointed to by S is '%c'\n", *s+4);

给出以下结果？

 Element 1 pointed to by S is 'a'
 Element 2 pointed …

我正在尝试在c ++中声明一个队列:

#include <queue>
......
......
queue<Process> *readyQueue = new queue<Process>;
.......

但我一直得到这个错误

在此范围内未声明'queue'

我错过了什么？当然,我创建了Process结构,所以问题不存在.有什么问题？

以下是我的代码:

<?php
    #put the info the user just inputed into a file for later retrival
    file_put_contents("test.txt",$_POST, FILE_APPEND);
?>

这是我在test.txt中得到的结果:

JaneF16xyzWindows1215

如何更改结果的格式

珍,女,16,XYZ,窗,12,15

(在元素之间有逗号)