我需要在提交表单之前预览图像.我使用Rails 3并需要与浏览器兼容的东西.有什么想法我能做到吗?
在更新之前一切正常.使用带有RVM的ruby 1.9.3p392和rails(3.2.12)使用MySQL 5.7.16和Nginx和Unicorn
日志显示
LoadError: libmysqlclient.so.18: cannot open shared object file: No such file or directory - /home/bill/apps/xxx/shared/bundle/ruby/1.9.1/gems/mysql2-0.3.16/lib/mysql2/mysql2.so
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我试过了:
bundle install没有任何效果.更新后有人遇到过这个问题吗?
我正在使用 ruby 3.0.1p64 并使用 macOS bigsur 11.04 mysql 安装并运行
捆绑安装要求我安装 mysql2
我正在尝试像这样安装 mysql2 gem:
sudo gem install mysql2 -v '0.5.3' --source 'https://rubygems.org/'
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我得到这个:
Building native extensions. This could take a while...
ERROR: Error installing mysql2:
ERROR: Failed to build gem native extension.
current directory: /Users/henri/.rbenv/versions/3.0.1/lib/ruby/gems/3.0.0/gems/mysql2-0.5.3/ext/mysql2
/Users/henri/.rbenv/versions/3.0.1/bin/ruby -I /Users/henri/.rbenv/versions/3.0.1/lib/ruby/3.0.0 -r ./siteconf20210617-53969-y4phap.rb extconf.rb
checking for rb_absint_size()... yes
checking for rb_absint_singlebit_p()... yes
checking for rb_wait_for_single_fd()... yes
*** extconf.rb failed ***
Could not create Makefile due to some reason, probably lack of necessary
libraries …Run Code Online (Sandbox Code Playgroud) 我正在使用Rails 3和carrierwave以及Rmagick.我想要将图片精确调整为192 x 135这个开始时很简单,但直到现在我才尝试过.
有人找到了解决方案吗?这是我的上传代码.
class AvatarUploader < CarrierWave::Uploader::Base
#Include RMagick or MiniMagick support:
include CarrierWave::RMagick
include CarrierWave::MiniMagick
# Choose what kind of storage to use for this uploader:
storage :file
# storage :fog
def store_dir
"uploads/#{model.class.to_s.underscore}/#{mounted_as}/#{model.id}"
end
# Provide a default URL as a default if there hasn't been a file uploaded:
def default_url
# # For Rails 3.1+ asset pipeline compatibility:
ActionController::Base.helpers.asset_path("fallback/" + [version_name, "default.png"].compact.join('_'))
#
# "/images/fallback/" + [version_name, "default.png"].compact.join('_')
end
process :resize_to_fit => [250, 250]
# …Run Code Online (Sandbox Code Playgroud) 希望可以有人帮帮我:
\n\n我的服务器上运行着许多站点,并且我正在使用 mariadb。\n当我这样做时:
\n\nsudo service mysql restart\nRun Code Online (Sandbox Code Playgroud)\n\n我得到:
\n\nJob for mariadb.service failed because the control process exited with \nerror code. See "systemctl status mariadb.service" and "journalctl -xe" \nfor details.\nRun Code Online (Sandbox Code Playgroud)\n\n\n\n\nsystemctl 状态 mariadb.service
\n
mariadb.service - MariaDB database server\n\n Loaded: loaded (/lib/systemd/system/mariadb.service; enabled; vendor preset: enabled)\n\n Drop-In: /etc/systemd/system/mariadb.service.d\n \xe2\x94\x94\xe2\x94\x80migrated-from-my.cnf-settings.conf\n Active: failed (Result: exit-code) since Thu 2017-09-14 03:16:51 UTC; 1min 6s ago\n Process: 13247 ExecStart=/usr/sbin/mysqld $MYSQLD_OPTS $_WSREP_NEW_CLUSTER $_WSREP_START_POSITION (code=\n Process: 13086 ExecStartPre=/bin/sh -c [ ! …Run Code Online (Sandbox Code Playgroud) 当我的服务器突然停止工作时,一切都运行得很顺利.我正在使用Linode和Nginx fast-cgi
这是我的日志文件:
上游超时(110:连接超时),同时从上游读取响应头,客户端:76.66.174.147,服务器:iskacanada.com,请求:"GET/HTTP/1.1",上游:"fastcgi://127.0.0.1: 9000",主持人:"www.iskacanada.com"
location ~ \.php$ {
include fastcgi_params;
fastcgi_read_timeout 120;
fastcgi_pass localhost:9000;
fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
}
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当我想重启mysql时,它说:
sudo service mysql restart stop:未知实例:start:作业无法启动
怎么知道发生了什么?
我知道变量在 go 中是按值传递的。但是,我想在此函数外的 func 内调用一个变量。让我给你举个例子:
package main
import (
"fmt"
)
func Smile(){
A := 5
}
func main() {
fmt.Println(A)
}
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这给了我 undefine A。
通过 A 的最佳方法是什么?我应该使用指针吗?我怎么做?