小编Sat*_*tti的帖子

我在Windows Phone中使用相机做应用程序.任何人都可以说,如何在使用Camera Capture点击后获取图像我想在其他页面中显示该图像,我想添加一些关于它的材料,而不是我喜欢保存.请任何一个指南我

我有带有Image Url的String Array

数组样本图片:

string Image = "https://fbcdn-profile-a.akamaihd.net/hprofile-ak-prn2/187738_100000230436565_1427264428_q.jpg";

现在我需要在Xaml中绑定图像

<Image Name="img" HorizontalAlignment="Left" VerticalAlignment="Top" Width="66" Height="66" Source="{Binding Image} " />

试图给img.source但不接受因为con't实现字符串到system.windows.media.imagesource

现在我正在将 .Net MVC 应用程序转换为 .Net Core App

要记录我们在 MVC 中使用“HttpContext”的事件

LoggerException loggerException = new LoggerException();
loggerException.ApplicationName = "Service";
loggerException.Level = logLevel;
loggerException.Timestamp = DateTime.UtcNow.ToString();
loggerException.UserController = HttpContext.Current.Request.Url.Segments[2];
loggerException.Action = HttpContext.Current.Request.Url.Segments[3];
loggerException.IpAddress = HttpContext.Current.Request.UserHostAddress;

在 .Net Core 中，“IHttpContextAccessor”是“HttpContext”的替代品。我无法获得用户控制器和操作

我当前的 .net 核心代码

LoggerException loggerException = new LoggerException();
loggerException.ApplicationName = appName;
loggerException.Level = logLevel;
loggerException.Timestamp = DateTime.UtcNow;
//loggerException.UserController = httpContextAccessor.HttpContext != null ? httpContextAccessor.HttpContext.User.ToString() : string.Empty;
//loggerException.Action = httpContextAccessor.HttpContext != null ? httpContextAccessor.HttpContext. : string.Empty;
loggerException.IpAddress = httpContextAccessor.HttpContext != null ? httpContextAccessor.HttpContext.Connection.RemoteIpAddress.ToString() : …

听到我将一些ObservableCollection数据绑定到我的文本块有一些时间差我没有任何动画显示数据,但我需要动画来显示.这是我的代码:

    DispatcherTimer timer = new DispatcherTimer();
    public ObservableCollection<ItemViewModel> Items { get; private set; }

    public Slideshow()
    {
        InitializeComponent();
        this.Items = new ObservableCollection<ItemViewModel>();
        DataContext = App.ViewModel;
        this.Items = App.ViewModel.Items;       
    }

    private void PhoneApplicationPage_Loaded_1(object sender, RoutedEventArgs e)
    {
        itemNumber = 0;
        Name.Text = this.Items[itemNumber].LineOne;
        if (!App.ViewModel.IsDataLoaded)
        {
            App.ViewModel.LoadData();
        }
        timer = new DispatcherTimer();
        timer.Interval = TimeSpan.FromSeconds(5);
        timer.Tick += new EventHandler(timer_Tick);
        itemNumber++;
        timer.Start();  
    }

    public void timer_Tick(object sender, EventArgs e)
    {
        if (this.Items.Count > 0)
        {
            itemNumber++;
            Name.Text = this.Items[itemNumber].LineOne;
            if …

通过按 Enter 键需要以下面的角度 4 提交表单是我表单中的代码Action = ""不起作用。我还尝试使用(keydown) = domonething(event)和(keydown.enter) = domonething(event) 使用以下代码

keyDownFunction(event) {
    if (event.keyCode == 13) {
        this.submit();
    }
}

下面是我当前的代码

<form #f="ngForm" (ngSubmit)="f.form.valid && openModal(confirmationmodal)" novalidate action="">
    <div class="form-group form-row">
        <label class="col-form-label col-sm-4 col-md-4" for="name">Employee Name</label>
        <div class="col-sm-8 col-md-8">
            <span type="text" readonly class="form-control-plaintext" id="name">{{employeeDetails.EmployeeName}}</span>
        </div>
    </div>
    <div class="form-group form-row">
        <label class="col-form-label col-sm-4 col-md-4 " for="name">Manager Name</label>
        <div class="col-md-8  col-sm-8">
            <span type="text" readonly class="form-control-plaintext"
                id="manager">{{employeeDetails.ManagerName}}</span>
        </div>
    </div>
    <div class="form-group form-row">
        <label for="name" class="col-sm-4 …