小编Pra*_*rve的帖子

我们无法对我们从中获得的集合执行<Collection>.add或<Collection>.addAll操作Arrays.asList..只允许删除操作.

那么如果我遇到需要添加新元素List而不删除以前元素的情况List怎么办？我怎样才能做到这一点？

我尝试安装browserify(npm模块)..我得到以下错误 -

praful@ubuntu:~/terminalcloud$ npm install -g browserify
npm http GET https://registry.npmjs.org/browserify

npm ERR! Error: failed to fetch from registry: browserify
npm ERR!     at /usr/share/npm/lib/utils/npm-registry-client/get.js:139:12
npm ERR!     at cb (/usr/share/npm/lib/utils/npm-registry-client/request.js:31:9)
npm ERR!     at Request._callback (/usr/share/npm/lib/utils/npm-registry-client    /request.js:136:18)
npm ERR!     at Request.callback (/usr/lib/nodejs/request/main.js:119:22)
npm ERR!     at Request.<anonymous> (/usr/lib/nodejs/request/main.js:212:58)
npm ERR!     at Request.emit (events.js:88:20)
npm ERR!     at ClientRequest.<anonymous> (/usr/lib/nodejs/request/main.js:412:12)
npm ERR!     at ClientRequest.emit (events.js:67:17)
npm ERR!     at HTTPParser.onIncoming (http.js:1261:11)
npm ERR!     at HTTPParser.onHeadersComplete (http.js:102:31)
npm ERR! You may report this log at:
npm ERR! …

TRUNCATE和DELETE命令执行相同的工作,在数据操作的情况下,为什么DELETE命令在DML命令下,TRUNCATE命令在DDL命令下？

我看过来

http://en.cppreference.com/w/cpp/string/basic_string/replace

http://en.cppreference.com/w/cpp/algorithm/replace

但这似乎只是一次字符串，我不想为for我拥有的每个字符运行一个。有没有办法用一个vector<string>或一些字符数组运行这个替换方法？

就像“我喜欢 l/e*m)o)ns”变成“我喜欢柠檬”。

replace(arrayOfcharacters, "");  something like that...

有办法吗？