小编use*_*133的帖子

我有多个div标签:

div保存内容的主要内容,如果内容变大,高度显然也会变大,但其他div则不然.

如何让其他div占据主div的高度？

码

<div id="container">
    <span id="header">Fiction Tools</span>
    <span id="paragraph">Lots of text will be in this text box, 
    describing in great detail the awesomeness of Fiction Tools 
    and it’s capabilities. Fiction Tools is known for lots of 
    awesome things, here are a few:</span>
    <ul id="lists">
        <li>We have this awesome design made by Driptone.</li>
        <li>Did I mention, the design is awesome? Well, it is.</li>
        <li>You should be reading this in the voice of Morgan Freeman.</li>
        <li>In a …

我从我的数据库中取出了两个数据并将它们分开,然后将$ Kdr打印出计算出的值.

<?php
    $query = mysql_query("SELECT * FROM `high` ORDER BY `$Kdr` DESC LIMIT 20");
    while($row = mysql_fetch_array($query)){
    if ($row["kills"] != 0) {
    $Kdr = $row["kills"] / $row["deaths"];
    }       
    echo "<tr><td><a href='personalhs.php?query={$row["playerName"]}'>".$row['Runecraftlvl']."</a></td><td>".$row['kills']."</td><td>".$row['Runecraftxp']."</td><td>".$Kdr."</td></tr>";
    }
?>

忽略$ row ['Runecraftinglvl']和其他人.

基本上我希望我的表通过我在上面声明的变量"$ Kdr"来打印分割数据.

我试过这样做:

    $query = mysql_query("SELECT * FROM `high` ORDER BY `" . $kdr . "` DESC LIMIT 20");

还有这个

    $query = mysql_query("SELECT * FROM `high` ORDER BY `$Kdr` DESC LIMIT 20");

两者都给我这个错误:警告:mysql_fetch_array()期望参数1是资源,第90行/home/justxpp1/public_html/gxx/highscores.php中给出的布尔值

我究竟做错了什么？谢谢.

我想将我的数字缩短一些,所以最大数字将是5.

例如,而不是

2.2333333333

它会显示出来

2.23333

我用过这段代码:

    echo "<tr><td>".$results['playerName']."</td><td>".$results['Runecraftlvl']."</td><td>".$results['Runecraftxp']."</td><td>".$results['kills']."</td><td>".$results['deaths']."</td><td>".$results['targkills']."</td><td>". $number_format("$Kdr",5)."</td></tr>";

在最后一个变量上

<td>". $number_format("$Kdr",5)."</td>

工作正常,但如果用户得到0 Kdr或其他东西,它将打印此错误:

致命错误:函数名称必须是字符串

为什么这样做？怎么修好？谢谢.