Add Expires headers
There are 21 static components without a far-future expiration date.
http://static.doers.lk/examples-offline.css
http://static.doers.lk/kendo.common.min.css
http://static.doers.lk/kendo.default.min.css
http://static.doers.lk/style.css
http://static.doers.lk/jquery.min.js
http://static.doers.lk/kendo.web.min.js
http://static.doers.lk/console.js
http://static.doers.lk/sprite.png
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
https://fbexternal-a.akamaihd.net/safe_image.php?...
http://static.doers.lk/favicon.PNG
当我使用雅虎YSLOW测试网站时,它说上面按摩.所以我不知道如何添加过期的标题.任何帮助将不胜感激？
我正在寻找快速有效的数据存储来构建我的基于PHP的网站.我知道MySql.我可以在服务器根目录而不是MySQL数据库中使用JSON文件吗？如果是的话,最好的方法是什么？
CSS:
.chash, .java, .php, .jscript, .jQuery, .cplus, .python, .asp, .dotnet, .html,
.objectivec, .iOS, .sql, .css, .rubyr, .c, .xml, .AJAX, .xcode, .linux, .windows,
.vbdotnet, .json, .Apache, .wordpress, .oracle, .Perl, .ActionScript, .flash,
.dothtaccess, .VisualStudio, .GoogleAppEngine, .jsp,. PostgreSQL, .ZendFramework,
.email, .GoogleMaps {
background: none repeat scroll 0 0 #FFFFFF;
box-shadow: 0 2px 15px rgba(0, 0, 0, 0.4);
margin: 10px;
padding: 5px;
width: 250px;
height: 180px;
}
td {
padding-right: 20px;
margin: 10px;
}
HTML:
<div class="Languages">
<table>
<tr>
<td class="chash"></td>
<td class="java"></td>
<td …我想知道如何使用YQL获取JSON数据.
这是我的JSON URL:
https://www.facebook.com/feeds/page.php?id=397319800348866&format=json
JavaScript的:
<script>
$('#alink').click(function () {
$("#loading").ajaxStart(function(){
$(this).show();
}).ajaxStop(function(){
$(this).hide();
});
$('#aresult').load('content2.html', function() {
$('#successdata').html('100% loaded');
});
});
</script>
HTML:
<a href="#" id="alink">click me</a>
<div id="aresult"></div>
这段代码有什么错误？我想在用户点击鼠标并加载图片时加载ajax调用页面
如果条件为真,如何从$ repvalue值写textarea值请帮助我.
<html>
<body>
<form action="find4.php" method="post" name="finrep">
<p>Find: <input type="text" name="fin">Replace: <input type="text" name="rep" >
</p>
<p><br/>
<textarea name="comments" cols="25" rows="5" value="<?php echo $repvalue; ?>"></textarea>
<input type="submit" name="submit1" value="submit">
</p>
</form>
</body>
</html>
<?php
if ($_POST['submit1'])
{
$findval = $_POST['fin'];
$textboval = $_POST['comments'];
if($findval == $textboval){
$repvalue = $_POST['rep'];
}
}
?>