我有以下代码用于提取tar.gz文件,同时密切关注进度:
from __future__ import division
import tarfile
import os
theArchive = "/Users/Dennis/Instances/atlassian-jira-enterprise-4.1.2-standalone.tar.gz"
a = tarfile.open(theArchive)
tarsize = 0
print "Computing total size"
for tarinfo in a:
tarsize = tarsize + tarinfo.size
realz = tarsize
print "compressed size: " + str(a.fileobj.size)
print "uncompressed size: " + str(tarsize)
tarsize = 0
for tarinfo in a:
print tarinfo.name, "is", tarinfo.size, "bytes in size and is",
if tarinfo.isreg():
print "a regular file."
elif tarinfo.isdir():
print "a directory."
else:
print "something else."
a.extract(tarinfo)
tarsize = …请参阅:http://pastebin.com/5za3uCi1
我是php的新手,我正在编辑ventrilo状态脚本.我想要它做的是它将所有内容存储在一个大变量中以便于解析,而不是使用单独的echo.谁能告诉我如何才能做到这一点？
谢谢,
丹尼斯
我正在使用python 2.6在OSX上创建一个非常简单的示例但我不断得到:
Traceback (most recent call last):
File "ssl.py", line 1, in <module>
import socket, ssl
File "/Users/Dennis/ssl.py", line 5, in <module>
sslSocket = ssl.wrap_socket(s)
AttributeError: 'module' object has no attribute 'wrap_socket'
码:
import socket, ssl
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect(('irc.freenode.net', 7000))
sslSocket = ssl.wrap_socket(s)
print repr(sslSocket.server())
print repr(sslSocket.issuer())
sslSocket.write('Hello secure socket\n')
s.close()
我做错了什么？
谢谢!
丹尼斯
出于某种原因,此代码会产生问题:
source="/foo/bar/"
destination="/home/oni/"
if [ -d $source ]; then
echo "Source directory exists"
if [ -d $destination ]; then
echo "Destination directory exists"
rsync -raz --delete --ignore-existing --ignore-times --size-only --stats --progress $source $destination
chmod -R 0755 $destination
else
echo "Destination directory does not exists"
fi
else
echo "Source directory does not exists"
fi
它出错了:
Source directory exists
/usr/bin/copyfoo: line 7: [: too many arguments
Destination directory does not exists
我之前在bash中使用嵌套的if语句没有问题,我忽略了什么简单的错误？
谢谢!
我得到了以下数据:
[{'name': 'SqueezePlay', 'power': '1', 'playerid': '91:e2:b5:24:49:63', 'ip': '192.168.1.144:51346', 'canpoweroff': 1, 'displaytype': 'none', 'seq_no': '10', 'connected': 1, 'isplayer': 1, 'model': 'squeezeplay', 'uuid': 'fgh79fg7h98789798978'}, {'name': "FLX's iPhone", 'power': '1', 'playerid': '4c:32:d1:45:6c:4e', 'ip': '84.105.161.205:53972', 'canpoweroff': 1, 'displaytype': 'none', 'seq_no': 0, 'connected': 1, 'isplayer': 1, 'model': 'iPengiPod', 'uuid': '9791c009e3e7fghfg346456456'}]
我改变了隐私价值的意义.我想根据"name"(例如"SqueezePlay")搜索数组,然后我将检索"playerid"(例如"91:e2:b5:24:49:63").
在Python中执行此操作的最有效方法是什么？谢谢!
如何在PHP中创建嵌套的条件语句？
我试着:
if (A=="blah" && B=="bleh" && C=="bloh" && (D=="bluh" || E=="blih"))
更易于阅读:
if (A AND B AND C AND (D OR E))