小编TAR*_*515的帖子

我遇到一个简单问题的麻烦.我会在HTTPServlet中获得真正的客户端IP.

从现在起我用过:

request.getRemoteAddr()

但现在它返回一个虚假的IP.例如:xxx.xxx.xxx.50,但我的IP类似于xxx.xxx.xxx.159.(查看http://whatismyipaddress.com/).

现在我试着用:

request.getHeader("X-Forwarded-For")

它返回NULL.

我还参加了以下课程的探测:

public class IpUtils {

public static final String _255 = "(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)";
public static final Pattern pattern = Pattern.compile("^(?:" + _255 + "\\.){3}" + _255 + "$");

public static String longToIpV4(long longIp) {
    int octet3 = (int) ((longIp >> 24) % 256);
    int octet2 = (int) ((longIp >> 16) % 256);
    int octet1 = (int) ((longIp >> 8) % 256);
    int octet0 = …