我一直在尝试为Angular2做快速入门指南.我按照快速指南中的说明做了例子.但是,当我运行它时,它显示以下消息'无法获取'.有谁知道为什么会这样？
boot.js文件
// JavaScript source code
(function (app) {
document.addEventListener('DOMContentLoaded', function () {
ng.platform.browser.bootstrap(app.AppComponent);
});
})(window.app || (window.app = {}));
app.component.js文件
(function (app) {
app.AppComponent = ng.core.Component({
Selector: 'my-app',
template: '<h1>My First Angular 2 App </h1>'
})
.class({
constructor: function () { }
});
})(window.app || window.app == {});
索引文件
<html>
<head>
<title>Angular 2 QuickStart</title>
<!-- 1. Load libraries -->
<script src="https://code.angularjs.org/2.0.0-beta.0/angular2-polyfills.js"></script>
<script src="https://code.angularjs.org/2.0.0-beta.0/Rx.umd.js"></script>
<script src="https://code.angularjs.org/2.0.0-beta.0/angular2-all.umd.dev.js"></script>
<!-- 2. Load our 'modules' -->
<script src='app/app.component.js'></script>
<script src='app/boot.js'></script>
</head>
<!-- 3. Display …我正在尝试使用RSA公钥加密邮件并使用我的私钥解密它.它加密了邮件,但我无法解密它.在最后的过程之后,消息仍然是加密的.当我导出私钥时,它还包括公钥.我试图删除公钥,但它不起作用.这是私钥和公钥
//This is the public key
private const string public_key = "<RSAKeyValue><Modulus>uznzVPilsR1rWPkpq6m6IALaafDnVZTDDcnEyBD3A/PBx2JZTKM0DTgiTDDwCEmQBNBpPILcIBdtg3aSUgicair+2ksYrVFT+uiy0Zy1nU6qoJ+SsapLKrpCa1zHpV4LMO/pFo4Foqzw0C1FNe56FXo1xj77GPgeYl0MHUVtAUc=</Modulus><Exponent>AQAB</Exponent></RSAKeyValue>";
//This is the private and public key.
private const String private_key = "<RSAKeyValue><Modulus>uznzVPilsR1rWPkpq6m6IALaafDnVZTDDcnEyBD3A/PBx2JZTKM0DTgiTDDwCEmQBNBpPILcIBdtg3aSUgicair+2ksYrVFT+uiy0Zy1nU6qoJ+SsapLKrpCa1zHpV4LMO/pFo4Foqzw0C1FNe56FXo1xj77GPgeYl0MHUVtAUc=</Modulus><Exponent>AQAB</Exponent><P>+jPKs9JxpCSzNY+YNanz49Eo/A6RaU1DZWoFm/bawffZOompeL1jzpUlJUIrKVZJkNFvlxE90uXVwjxWBLv9BD==</P><Q>v5CVWKZ5Wo7W0QyoEOQS/OD8tkKS9DjzZnbnuo6lhcMaxsBrCWLstac1Xm2oFNtZgLtrPGbPfCNC5Su4Rz/P5w==</Q><DP>ZnyikmgobqEt20m3gnvcUDxT+nOJMsYYTklQhONoFj4M+EJ9bdy+Lle/gHSLM4KJ3c08VXgVh/bnSYnnfkb20Q==</DP><DQ>sSYGRfWk0W64Dpfyr7QKLxnr+Kv186zawU2CG44gWWNEVrnIAeUeWxnmi41CWw9BZH9sum2kv/pnuT/F6PWEzw==</DQ><InverseQ>XpWZQKXa1IXhF4FX3XRXVZGnIQP8YJFJlSiYx6YcdZF24Hg3+Et6CZ2/rowMFYVy+o999Y5HDC+4Qa1yWvW1vA==</InverseQ><D>Kkfb+8RrJqROKbma/3lE3xXNNQ7CL0F5CxQVrGcN8DxL9orvVdyjlJiopiwnCLgUHgIywceLjnO854Q/Zucq6ysm2ZRq36dpGLOao9eg+Qe8pYYO70oOkEe1HJCtP1Laq+f3YK7vCq7GkgvKAI9uzOd1vjQv7tIwTIADK19ObgE=</D></RSAKeyValue>";
//Encrypting the text using the public key
private RSACryptoServiceProvider cipher = null;
cipher = new RSACryptoServiceProvider();
cipher.FromXmlString(public_key);
byte[] data = Encoding.UTF8.GetBytes(txtUnencrypt.Text);
byte[] cipherText = cipher.Encrypt(data, false);
lblUnencryptMessage.Text = Convert.ToBase64String(cipherText);
// decryptText();
//Trying to decrypt the text using the private key
cipher = new RSACryptoServiceProvider();
cipher.FromXmlString(private_key);
byte[] ciphterText = Convert.FromBase64String(lblUnencryptMessage.Text);
byte[] plainText = cipher.Decrypt(ciphterText, false);
lblDecript.Text …我试图检查用户名是否是base64字符串.即使字符串是base64编码,它仍然会抛出非法异常错误消息.我在这里错过了什么？
public bool checkBase64String(string value) //value = “TWrXfr4gGTE%3d”
{
try
{
byte[] vArray = Convert.FromBase64String(value);
return true;
}
catch (FormatException ex)
{
ex.ToString();
}
return false;
}
输入不是有效的Base-64字符串,因为它包含非基本64个字符,两个以上的填充字符或填充字符中的非法字符.