我有以下HTML源代码
<form name="Register1" action="Register.aspx" id="registerform" method="post"
runat="server" style="margin-top: 15px;">
<input type="radio" name="Gender" value="male" />male
<input type="radio" name="Gender" value="female" />female
</form>
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我的问题是如何在c#页面中将所选值变为变量?
我试过这个:
Gender = Request.Form["Gender"].ToString();
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但它不起作用......
我有以下C#代码:
ArticleContent = ds1.Tables[0].Rows[i]["ArticleContent"].ToString();
if (ArticleContent.Length > 260)
{
ArticleContent = ArticleContent.Remove(ArticleContent.IndexOf('.', 250)) + "...";
}
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这里的问题是我收到此错误消息:
StartIndex不能小于零.
为什么以及如何解决它?
我有这个CSS + HTML代码:
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8" />
<title>What</title>
<style type="text/css">
#page {
width: 900px;
padding: 0px;
margin: 0 auto;
direction: rtl;
position: relative;
}
#box1 {
position: relative;
width: 500px;
border: 1px solid black;
box-shadow: -3px 8px 34px #808080;
border-radius: 20px;
box-shadow: -8px 5px 5px #888888;
right: 300px;
top: 250px;
height: 150px;
-webkit-transition: all 1s;
font-size: large;
color: Black;
padding: 10px;
background: #D0D0D0;
opacity: 0;
}
@-webkit-keyframes myFirst {
0% {
right: 300px;
top: 150px; …Run Code Online (Sandbox Code Playgroud) 我有以下CSS:
.main {
padding-right: 15px;
padding-left: 15px;
/* IE9 SVG, needs conditional override of 'filter' to 'none' */
background: url(data:image/svg+xml;base64,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)top;
background: -moz-linear-gradient(top, rgba(229,229,229,1) 0%, rgba(255,255,255,0) 100%)top; /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(229,229,229,1)), color-stop(100%,rgba(255,255,255,0)))top; /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%)top; /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%)top; /* IE10+ */
background: linear-gradient(to bottom, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%) top; /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#e5e5e5', endColorstr='#00ffffff',GradientType=0 )top; …Run Code Online (Sandbox Code Playgroud) 我有一个简单的问题,但我无法在网上罚款.
我有这个HTML代码:
<form name="Register" action="Register.aspx" method="post" runat="server" style="margin-top: 15px;" onsubmit="return validateProfile(this);" >
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这个JavaScript代码
function validateProfile(F) {
var G = F.name;
}
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我想以某种方式获取表单名称,但此代码不起作用.
希望得到帮助,谢谢!
我有以下C#代码:
int[,] mt = { { 5, 4, 6, 2 }, { 8, 1, 5, 4 }, { 2, 3, 8, 6 }, { 9, 6, 1, 8 } };
int i, min, index, j, v;
for (i = 0; i < mt.GetLength(1); i++)
{
index = 0;
min = int.MaxValue;
for (j = 0; j < mt.GetLength(0); j++)
{
v = mt[j, i];
if (v < min)
{ min = mt[j, i]; index = j; }
}
mt[i, index] …Run Code Online (Sandbox Code Playgroud) 我有以下PHP代码:
<?php
if (!(session_id('password')) || !(session_id('user_name'))) {
header("Location: ../../"); /* Redirect browser */
}
?>
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哪个应该检查会话是否存在,如果不存在,用户重定向,问题是这个条件总是如此,即使会话确实存在,我的问题是如何解决它?
我有以下PHP代码:
$allowedExts = array("gif", "jpeg", "jpg", "png", "PNG", "JPG", "JPEG", "GIF");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = end($temp);
if ((($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/jpeg")
|| ($_FILES["file"]["type"] == "image/jpg")
|| ($_FILES["file"]["type"] == "image/pjpeg")
|| ($_FILES["file"]["type"] == "image/x-png")
|| ($_FILES["file"]["type"] == "image/png"))
&& ($_FILES["file"]["size"] < 2000000)
&& in_array($extension, $allowedExts)) {
if ($_FILES["file"]["error"] > 0) {
echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
} else {
$file_name = "images/".$_FILES["file"]["name"];
if (file_exists("../images/" . $_FILES["file"]["name"])) {
echo $_FILES["file"]["name"] . " already exists. …Run Code Online (Sandbox Code Playgroud) 我有一个包含链接的字符串.例:
www.google.com;www.yahoo.com;www.gmail.com
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我的问题是我如何分离这些链接,以便我可以添加标签的所有链接<a>以及链接末尾的标记</a>?
我应该得到这个:
<a>www.google.com</a>;<a>www.yahoo.com</a>;<a>www.gmail.com</a>
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如果解决方案尽可能简单并使用该IndexOf方法,我将感激不尽.
我知道这可能是一个非常简单的问题,我试图在网上找到解决方案,但我无法理解......我有以下C#/ ASPX代码:
SelectArea += "<select name=\"Area\" id=\"area\">" + "<option value=\"Default\" style=\"display:none;\">SELECT AREA</option>";
for (i = 0; i < ds.Tables[0].Rows.Count; i++)
{
AreaName = ds.Tables[0].Rows[i]["AreaName"].ToString();
SelectArea += string.Format("<option value=\"{0}\"/>{0}</option>", AreaName);
}
SelectArea += "</select>";
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这个javascript函数在提交后发生
function validateProfile() {
var el = document.getElementById("area").value;
alert(el);
}
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我想要一些如何获取列表中所选值的编号.我试过上面的代码,但它不起作用.
希望得到帮助,谢谢!