小编Fra*_*sco的帖子

我按照Symfony关于功能测试的文档来编写我的第一个,但是我有一些问题.我通过浏览器得到的响应很好:

但是当我phpunit -c app/在shell中运行时,我会失败.

1)AppBundle\Tests\Controller\MeterAPIControllerTest :: testGetAllVariables声明500匹配预期200失败.

这是代码:

<?php

namespace AppBundle\Tests\Controller;

use Symfony\Bundle\FrameworkBundle\Test\WebTestCase;

class MeterAPIControllerTest extends WebTestCase
{
    public function testGetAllVariables()
    {
        $client = static::createClient();
        $crawler = $client->request(
            'GET',
            '/meters/121/120/variables'
        );

        // Assert a specific 200 status code
        $this->assertEquals(200, $client->getResponse()->getStatusCode()); 
    }
}

如果我尝试另一个测试断言,我也会失败.

// Assert that the "Content-Type" header is "application/json"
$this->assertTrue(
    $client->getResponse()->headers->contains(
        'Content-Type',
        'application/json'
    )
);

编辑

当我运行时phpunit,app/logs/test.log我得到一个PHP异常:

[2016-03-31 15:25:21] request.CRITICAL:未捕获的PHP Exception Doctrine\Common\Persistence\Mapping\MappingException:"类AppBundle\Entity的映射文件'AppBundle.Entity.EM2Meter.orm.yml'无效\ EM2Meter"." at /Applications/MAMP/htdocs/iso50k1_tst_symfony/vendor/doctrine/common/lib/Doctrine/Common/Persistence/Mapping/MappingException.php第86行{"exception":"[object](Doctrine\Common\Persistence\Mapping\MappingException) (代码:0):类'AppBundle\Entity\EM2Meter'的映射文件'AppBundle.Entity.EM2Meter.orm.yml'无效.在/ Applications/MAMP/htdocs/iso50k1_tst_symfony/vendor/doctrine/common/lib/Doctrine/Common/Persistence/Mapping/MappingException.php:86)"} [] …

我曾经json_encode($array);把数组转换为json.

[{"x":1418736600,"y":"82.2"},{"x":1418736900,"y":"82.2"}]

但我真正需要的是一个JavaScript对象,如下所示:

[{x:1418736600,y:"82.2"},{x:1418736900,y:"82.2"}]

为了简化它我想要一个没有引用键的JSON,但最好避免解析什么json_encode输出并使用更直接的方式.

是否可以在PHP中执行此操作？