小编Shu*_*uma的帖子

刚开始制作网站，整个左侧的边缘只有几像素，所以我不知道为什么。

http://jsbin.com/elufob/1/

任何建议将不胜感激

的CSS

    html{
    min-width: 100%;
    background-color: #add8e6;
}

.navBar{
    text-align: center;
    background-image: linear-gradient(to bottom, #666666 0%, #000000 60%);
    color: white;
    border-bottom:solid 1px #666;
    top:0;
    height:30px;
    position:fixed;
    width:100%;
    z-index:1000;
}

.leftDiv{
    clear: left;
    text-align: left;
    background-color: blue;
    float: left;
    max-width: 26%;
    display: inline-block;
    margin-right:2%;
    margin-left: 0%;
    margin-top: 2%;
    border: black;
    border-width: 5px;
    border-style: double;
    border-radius: 5px;
}

.middleDiv{
    text-align: center;
    background-color: green;
    max-width: 70%;
    float: right;
    display: inline-block;
    margin-top: 2%;
    MARGIN-BOTTOM: 1%;
    border-style: solid;
    border: black;
    border-width: 5px;
    border-style: …

我想知道是否可以存储图像

<input type="file" id="image">

本地.我是否必须存储图像,还是只需存储图像位置？

对于上下文,它来自一个从输入表单中获取名称,地址等的表单,创建一个对象,将其存储在一个数组中并显示该数组.

我正在努力找到通过附加功能的javascript/jquery添加按钮的正确语法.

现在我正在尝试:

list.append("<button onclick='getFeed('http://open.live.bbc.co.uk/weather/feeds/en/PA2/3dayforecast.rss, showFeedResults')'>ButtonTest</button>");

但它返回:

<button onclick="getFeed(" http:="" open.live.bbc.co.uk="" weather="" feeds="" en="" pa2="" 3dayforecast.rss,="" showfeedresults')'="">ButtonTest</button>

从本质上讲,我希望能够创造

<button onclick="getFeed('http://open.live.bbc.co.uk/weather/feeds/en/B1/3dayforecast.rss', showFeedResults)" class="ui-btn-hidden">

在javascript中,但无法弄清楚如何......

而且我似乎无法绕过创建使用单个和双重qoutation标记的html元素.

任何建议将不胜感激.

我在使用Java中的方法时遇到问题,这会导致错误:

Exception in thread "main" java.lang.NullPointerException
at FamilyTree$FamilyTreeNode.access$9(FamilyTree.java:5)
at FamilyTree.displayFamilyMember(FamilyTree.java:166)
at FamilyTreeTest.main(FamilyTreeTest.java:28)

问题的方法是:

public void displayFamilyMember(){  
    boolean cascade = false;    
     int memberIdentifier;              
     displayFamily();
     memberIdentifier = Input.getInteger("Input member ID");
     currentNode = ancestor ;
        if (currentNode.identifier == memberIdentifier || currentNode.partner.identifier == memberIdentifier){
            cascade = true;
            if(currentNode.partner!= null){
                System.out.println(currentNode.Name + " ID[" + currentNode.identifier + "] Partner:  " + currentNode.partner.Name + " ID[" + currentNode.partner.identifier + "]");
                }else{
                    System.out.println(currentNode.Name + " ID[" + currentNode.identifier + "] has no partner");
                }
            }           
        if(currentNode.child != …