我有一个我在我的应用程序上使用的cookie.它看起来像这样:
+-------+-------+-----------------------+-------+----------+
| Name | Value | Domain | Path | Expires |
+-------+-------+-----------------------+-------+----------+
| foo | bar | my.domain.tld | / | Session |
+-------+-------+-----------------------+-------+----------+
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在我的脚本的一部分中,基于某些条件,我正在尝试更改cookie的值.我正在使用此代码:
// overwrite cookie
if($condition){
setcookie("foo", "cat", 0, "/", "my.domain.tld");
}
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之后,我的cookie数据如下所示:
+-------+-------+-----------------------+-------+----------+
| Name | Value | Domain | Path | Expires |
+-------+-------+-----------------------+-------+----------+
| foo | bar | my.domain.tld | / | Session |
| foo | cat | .my.domain.tld | / | Session |
+-------+-------+-----------------------+-------+----------+
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为什么.要将a 添加到域名之前?我想覆盖现有的cookie.
我正在尝试子类化使用单例模式的类,并使用子类填充实例.
我好像有点麻烦.
class Singleton {
static private $instance;
static public function instance(){
if(is_null(self::$instance)){
self::$instance = new self();
}
return self::$instance;
}
private function __construct(){}
}
class MySingleton extends Singleton {
}
echo get_class(MySingleton::instance()); //=> Singleton
//=> I'm hoping to see MySingleton
Run Code Online (Sandbox Code Playgroud) 好吧,所以我在google中搜索,你在输入中输入文字,它会立即为你提供条目.但我不喜欢那样.我使用类似的东西$("TEXTINPUT").keyup(function() {.当用户输入速度非常快时,它会多次连接到数据库.是否有可能,只有当用户停止键入1-2秒,我们才会连接到PHP文件,但不是立即?我需要在jQuery中这样做.谢谢.
class A
private
def foo
puts :foo
end
public
def bar
puts :bar
end
private
def zim
puts :zim
end
protected
def dib
puts :dib
end
end
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a = A.new
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a.foo rescue puts :fail
a.bar rescue puts :fail
a.zim rescue puts :fail
a.dib rescue puts :fail
a.gaz rescue puts :fail
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fail
bar
fail
fail
fail
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[:foo, :bar, :zim, :dib, :gaz].each { |m| a.send(m) rescue puts :fail }
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foo
bar
zim
dib
fail
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标有"测试输出"的部分是预期结果.那么为什么我可以简单地访问私有/受保护的方法 …
有点像:
def domain_exists?(domain)
# perform check
# return true|false
end
puts "valid!" if domain_exists?("example.com")
Run Code Online (Sandbox Code Playgroud) 我正在寻找特定于Rails的TDD资源.
我已经看过Rails指南:创建Rails插件的基础知识,这真的激发了我对该主题的兴趣.
我有一本Agile Development with Rails书,我看到那里有一些与测试相关的信息.但是,似乎作者会引导您完成构建应用程序的步骤,然后再添加测试.这不是真正的测试驱动开发.
理想情况下,我想要一本关于此的书,但如果不存在这样的书,那么其他教程或文章的集合会很棒.
我想学的东西:
谢谢你的帮助!
Ruby怎么做到这一点?Jörg或其他任何人都知道幕后发生了什么吗?
不幸的是我不太了解C,所以bignum.c对我没什么帮助.我有点好奇,有人可以用简单的英语解释它使用的奇迹算法背后的理论.
irb(main):001:0> 999**999
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368063488259223267894700840060521865838338232037353204655959621437025609300472231530103873614505175218691345257589896391130393189447969771645832382192366076536631132001776175977932178658703660778465765811830827876982014124022948671975678131724958064427949902810498973271030787716781467419524180040734398996952930832508934116945966120176735120823151959779536852290090377452502236990839453416790640456116471139751546750048602189291028640970574762600185950226138244530187489211615864021135312077912018844630780307462205252807737757672094320692373101032517459518497524015120165166724189816766397247824175394802028228160027100623998873667435799073054618906855460488351426611310634023489044291860510352301912426608488807462312126590206830413782664554260411266378866626653755763627796569082931785645600816236891168141774993267488171702172191072731069216881668294625679492696148976999868715671440874206427212056717373099639711168901197440416590226524192782842896415414611688187391232048327738965820265934093108172054875188246591760877131657895633586576611857277011782497943522945011248430439201297015119468730712364007639373910811953430309476832453230123996750235710787086641070310288725389595138936784715274150426495416196669832679980253436807864187160054589045664027158817958549374490512399055448819148487049363674611664609890030088549591992466360050042566270348330911795487647045949301286614658650071299695652245266080672989921799342509291635330827874264789587306974472327718704306352445925996155619153783913237212716010410294999877569745287353422903443387562746452522860420416689019732913798073773281533570910205207767157128174184873357050830752777900041943256738499067821488421053870869022738698816059810579221002560882999884763252161747566893835178558961142349304466506402373556318707175710866983035313122068321102457824112014969387225476259342872866363550383840720010832906695360553556647545295849966279980830561242960013654529514995113584909050813015198928283202189194615501403435553060147713139766323195743324848047347575473228198492343231496580885057330510949058490527738662697480293583612233134502078182014347192522391449087738579081585795613547198599661273567662441490401862839817822686573112998663038868314974259766039340894024308383451039874674061160538242392803580758232755749310843694194787991556647907091849600704712003371103926967137408125713631396699343733288014254084819379380555174777020843568689927348949484201042595271932630685747613835385434424807024615161848223715989797178155169951121052285149157137697718850449708843330475301440373094611119631361702936342263219382793996895988331701890693689862459020775599439506870005130750427949747071390095256759203426671803377068109744629909769176319526837824364926844730545524646494321826241925107158040561607706364484910978348669388142016838792902926158979355432483611517588605967745393958061959024834251565197963477521095821435651996730128376734574843289089682710350244222290017891280419782767803785277960834729869249991658417000499998999
我正在制作内部使用的宝石.在其中,我从另一个目录加载一些YAML:
# in <project_root>/bin/magicwand
MagicWand::Configuration::Initializer.new(...)
# in <project_root>/lib/magicwand/configuration/initializer.rb
root_yaml = YAML.load_file(
File.expand_path("../../../../data/#{RootFileName}", __FILE__))
# in <project_root>/data/root.yaml
---
apple: 100
banana: 200
coconut: 300
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我宁愿不依赖于data/root.yaml相对的位置initializer.rb.相反,我宁愿得到一个参考<project_root>并依赖于那里的相对路径,这似乎是一个更聪明的举动.
首先,这是最好的方法吗?其次,如果是这样,我该怎么做?我检查了各种File方法,但我不认为有类似的东西.我正在使用Ruby 1.9.
现在,我创建一个特殊的常量并依赖于它:
# in lib/magicwand/magicwand.rb
module MagicWand
# Project root directory.
ROOT = File.expand_path("../..", __FILE__)
end
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但我也不确定我是否喜欢这种方法.
def my_func(foo,bar,*zim)
[foo, bar, zim].collect(&:inspect)
end
puts my_func(1,2,3,4,5)
# 1
# 2
# [3, 4, 5]
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function my_func($foo, $bar, ... ){
#...
}
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在PHP中执行此操作的最佳方法是什么?
当我写下面的代码时:
x= [1,2,3]
x << x
puts x
puts x[3]
puts x[3][3][3][3][3][3][3][3][3][3]
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我得到这个输出:
[1, 2, 3, [...]]
[1, 2, 3, [...]]
[1, 2, 3, [...]]
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我不应该只得到[1,2,3,[1,2,3]],这将是什么解释?