小编use*_*255的帖子

Concat JS无法正常工作

var myjson = '{"name": "cluster","children": [';

for (var i = 0; i < unique.length; i++)
{
    var uniquepart = '{"' + unique[i] + '"';
    myjson.concat(uniquepart); 
    var sizepart = ', "size:"';
    myjson.concat(sizepart);
    var countpart = count[i] + '';
    myjson.concat(countpart);
    if (i == unique.length) {
        myjson.concat(" },");
    }
    else {
        myjson.concat(" }");
    }
} 

var ending = "]}";
myjson.concat(ending);

console.log(myjson);
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有谁知道为什么这个字符串没有正确连接,我仍然最终得到原始值?

javascript string concat

4
推荐指数
2
解决办法
7310
查看次数

{name:"Name",值:1}是无效的JSON?

我有一个字符串,我试图将其转换为JSON对象并使用语法,var json = JSON.parse(myjson);但它说的是预期令牌}但我看不到哪里?

有谁知道这会是什么?

[{name:"After", value:1},{name:"watching", value:1},{name:"you", value:1},{name:"at", value:3},{name:"Birmngm", value:1},{name:"my", value:1},{name:"new", value:2},{name:"athlete", value:1},{name:"to", value:1},{name:"follow.", value:1},{name:"Love", value:2},{name:"the", value:4},{name:"passion,", value:1},{name:"enthusiasm", value:1},{name:"and", value:3},{name:"big", value:1},{name:"smiles!!", value:1},{name:"Long", value:1},{name:"may", value:1}]
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javascript json

-1
推荐指数
1
解决办法
123
查看次数

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javascript ×2

concat ×1

json ×1

string ×1