小编alf*_*ofu的帖子

正如标题所述.以下代码显示错误:

#include <iostream>
using namespace std;

class link
{
    public:
        link()
        {
            num=0;
            next=NULL;
        }

        int num; 
        link* next;
};

int main() {
    link test;

    return 0;
}

编译此代码

g++ test.cpp -o test

我的g ++版本是

g ++(Ubuntu/Linaro 4.6.3-1ubuntu5)4.6.3

编译器显示以下错误

test.cpp: In function ‘int main()’:
test.cpp:18:10: error: expected ‘;’ before ‘test’

如果我评论这个'链接测试'声明,那么一切都好.此外,如果我用'Link'等其他名称替换'link',一切都还可以.

在Visual Studio或VC中,代码没问题....所以它非常困惑我.

最近,我需要声明一个字符串数组,所以我写下了以下语句:

const char** directories = {"cricket_batting", "cricket_bowling", "croquet", "tennis_forehand", "tennis_serve", "volleyball_smash"};

但是,g ++向我显示了错误:

error: scalar object ‘directories’ requires one element in initializer

所以我把声明改为:

const char* directories[] = {"cricket_batting", "cricket_bowling", "croquet", "tennis_forehand", "tennis_serve", "volleyball_smash"};

这一次,这是对的.但我不能确切地知道之间的区别char**和char[].