小编Tho*_*lby的帖子

我创建了自己的FacebookBundle和

我收到了这个错误:

没有扩展程序可以加载"facebookbundle"的配置(在/facebookx/app/config/config_dev.yml中).寻找命名空间"facebookbundle",找到"framework","security","twig","monolog","swiftmailer","assetic","doctrine","sensio_framework_extra","jms_aop","jms_di_extra","jms_security_extra ","d_facebook","d_user","d_security","web_profiler","sensio_distribution"

错误消息意味着我在My config.yml中有一个条目"facebookbundle",任何扩展都没有使用它？

我的config.yml

facebookbundle:
    file:   %kernel.root_dir%/../src/FacebookBundle/Facebook/FacebookInit.php
    alias:  facebook
    app_id: xxx
    secret: xxx
    cookie: true
    permissions: [email, user_birthday, user_location, user_about_me]

我的DFacebookExtension

<?php

namespace D\FacebookBundle\DependencyInjection;

use Symfony\Component\DependencyInjection\ContainerBuilder;
use Symfony\Component\Config\FileLocator;
use Symfony\Component\HttpKernel\DependencyInjection\Extension;
use Symfony\Component\DependencyInjection\Loader;

/**
 * This is the class that loads and manages your bundle configuration
 *
 * To learn more see {@link http://symfony.com/doc/current/cookbook/bundles/extension.html}
 */
class DFacebookExtension extends Extension
{
    /**
     * {@inheritDoc}
     */
    public function load(array $configs, ContainerBuilder $container)
    {
        $configuration = new Configuration();
        $config = $this->processConfiguration($configuration, …

对于初学者,我正在寻找关于symfony2中的ajax的简单教程/示例？

我有这些例子:

• city.php:http://pastebin.com/Qm8LS5kh

• ajax_req.js:http://pastebin.com/UqJMad24

• index.html:http://pastebin.com/H1err4Yh

如何将这些内容放入Symfony2应用程序？

在创建和删除对象之后,我重定向到相同的操作(indexAction).创建之后,我想将此引导消息呈现为flash消息:

<div class="alert alert-success" role="alert">
  <a href="#" class="alert-link">...</a>
</div>

但删除后,我想渲染另一个html块:

<div class="alert alert-danger" role="alert">
  <a href="#" class="alert-link">...</a>
</div>

将此传递给Flash消息的最佳方法是什么？因为,我认为传递所有HTML不是个好主意？

$this->get('session')->getFlashBag()->add(
        'notice',
        '<div class="alert alert-danger" role="alert">
             <a href="#" class="alert-link">...</a>
         </div>'
    );

有没有更好的方法来解决这个问题？

我想从匿名函数返回值。如何在下面的代码中将返回值分配给 $id 变量？

$(document).on("click", '.delete-component', function(e) {
     return 4;
 });

 //$id in this scope should be equal 4

我有那个代码.但当我进入浏览器app_dev.php/login浏览器说:该页面重定向过多

security.yml security:encoders:Symfony\Component\Security\Core\User\User:plaintext

role_hierarchy:
    ROLE_ADMIN:       ROLE_USER
    ROLE_SUPER_ADMIN: [ROLE_USER, ROLE_ADMIN, ROLE_ALLOWED_TO_SWITCH]

providers:
    user_db:
        entity: { class: DotfusionMerlinBundle:User, property: username }

firewalls:
    dev:
        pattern:  ^/(_(profiler|wdt)|css|images|js)/
        security: false

    secured_area:
        pattern:  ^/
        anonymous: ~
        form_login:
            check_path: /login_check
            login_path: /login
        logout:
            path:   login
            target: login
        #anonymous: ~
        #http_basic:
        #    realm: "Secured Demo Area"

access_control:
    - { path: ^/login, roles: IS_AUTHENTICATED_ANONYMOUSLY }
    #- { path: ^/login, roles: IS_AUTHENTICATED_ANONYMOUSLY, requires_channel: https }

使用routing.yml

login:
    pattern:  /login
    defaults: { _controller: DotfusionMerlinBundle:User:login }

login_check:
    pattern:  /login_check