小编Tim*_* S.的帖子

Java simple for循环不会迭代

在执行期间,调用该方法,整数i显示0在屏幕上.但是,for循环内部没有输出,表明for循环没有执行.我还用断点测试了它,并获得了相同的结果.任何帮助表示赞赏.

i

private void decrypt_btnActionPerformed(java.awt.event.ActionEvent evt) {
    int ciphertext_length = Ciphertext().length();
    String decrypted_char = "";
    int i = 0;

    System.out.println("increment" + i);    

    try {
        for (i = 0; i == ciphertext_length; i++) {

            System.out.println("test" + i);

            String cipher_current_char = getLetterAtIndex(Ciphertext(), i);
            int pos_char_in_alphabet = getIndexAtLetter(Alphabet(), cipher_current_char);

            decrypted_char = decrypted_char +
                getLetterAtIndex(Alphabet(), pos_char_in_alphabet - 5);

            status_label.setText(100 / i + "%");
        }
    } catch (Exception e) {
        e.getMessage();
    }

    plain_ta.setText(decrypted_char);
}
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java loops for-loop

2
推荐指数
1
解决办法
178
查看次数

正确使用for循环

在以下代码中,永远不会执行for循环.我试图用断点和手表解决问题.返回密文的正确长度,但for循环直到没有增加int i >= ciphertext.length().事实上,似乎没有任何东西执行过'Debug'消息.

private void decrypt_btnActionPerformed(java.awt.event.ActionEvent evt) {                                            


    String alphabet= "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
    String ciphertext="fRcXFBxXTRJ";


    status_label.setText( "Decryption has begun" );

    JOptionPane.showMessageDialog(null,"ciphertext-length: " + ciphertext.length() + "\n" + ciphertext,"Debug", JOptionPane.INFORMATION_MESSAGE);

    for (int i = 0; i>=ciphertext.length(); i--){

        System.out.println("inc:" + i);

        String cipher_current_char = getLetterAtIndex(ciphertext, i);
        int pos_char_in_alphabet = getIndexAtLetter(alphabet, cipher_current_char);


        if(pos_char_in_alphabet-2<0){

            plain_ta.setText(getLetterAtIndex(alphabet, (alphabet.length()+(pos_char_in_alphabet -2)+1 ) ));

            status_label.setText( 100/i + "%");



        }else{

            cipher_current_char = getLetterAtIndex(ciphertext, i);

            pos_char_in_alphabet = getIndexAtLetter(alphabet, cipher_current_char);

            plain_ta.setText(getLetterAtIndex(alphabet, (pos_char_in_alphabet-2)));

            status_label.setText( 100/i + "%");

        }
    }
}                          
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java string loops for-loop

0
推荐指数
1
解决办法
90
查看次数

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for-loop ×2

java ×2

loops ×2

string ×1