小编Add*_*ddy的帖子

我正在进行参数化查询,但我没有得到正确的查询结果

这是我的代码

   public MySqlCommand Get_Login(string clinetID, string loginID, string password, string branchID)
    {
        MySqlCommand objCommand = new MySqlCommand(this.Query);


        objCommand.Parameters.AddWithValue("@ClientID", clinetID);
        objCommand.Parameters.AddWithValue("@LoginID", loginID);
        objCommand.Parameters.AddWithValue("@Password", password);
        objCommand.Parameters.AddWithValue("@BranchID", branchID);

        objCommand.CommandType = CommandType.Text;
        return objCommand;
    }

在调试时这是我在"objCommand"中得到的

 Select u.groupid,p.PersonId, p.designationid,concat(p.salutation,p.FName,'
',p.MName,' ',p.LName) as PersonName,tb.Type
 BrType,p.OrgId,p.subdepartmentid,ifnull(crossdept,'N') as
 crossdept,p.departmentid,u.defaultpage,p.orgid,ifnull(p.crosslab,'N') as crosslab,
 (select indoor_services from dc_Tp_organization where orgid='@ClientID') as
 indoor_services,(select name from dc_Tp_organization where orgid='@ClientID') as 
 orgname,
 (select default_route from dc_Tp_organization where orgid='@ClientID') as
 default_route,p.BranchID BranchID,tb.Name BRName from dc_tp_personnel p left outer
  join
 dc_tu_userright u on u.personid=p.personid …

我试图从单元格值中删除一部分但它不起作用.

单元格的示例内容:(示例输入)

="*sls*lmt"&CONCATENATE("_",'C:\Users\Administrator\AppData\Roaming\Microsoft\AddIns\XL-EZ Addin.xla'!COLUMNLETTER(C14),TEXT(ROW(),"0"))&"_sel*range(status)*0*GOOD|OK|0|#00D700|0|100|80*NOT GOOD|NG|0|#FFFF00|0|79|50*FAULTED|FAULTED|0|#FF0000|1|49|0"

样本输出:

="*sls*lmt"&CONCATENATE("_",!COLUMNLETTER(C14),TEXT(ROW(),"0"))&"_sel*range(status)*0*GOOD|OK|0|#00D700|0|100|80*NOT GOOD|NG|0|#FFFF00|0|79|50*FAULTED|FAULTED|0|#FF0000|1|49|0"

我想从价值中删除这部分

'C:\Users\Administrator\AppData\Roaming\Microsoft\AddIns\XL-EZ Addin.xla'

这是我尝试过的

Sub UpdateSheetButton()
Dim subStr1 As String
Dim subSrrt2 As String

Dim pos As Integer

For Each Cell In ActiveSheet.UsedRange.Cells
pos = InStr(Cell.Value, "'C:\")
If pos >= 1 Then
  subStr1 = Split(Cell.Value, "'C:\", 1)
  subStr2 = Split(Cell.Value, "\AddIns\XL-EZ Addin.xla'", 2)
  Cell.Value=subStr1 +subStr2 
  End If
Next

End Sub

错误: 运行时错误'13'在此行上键入不匹配

pos = InStr(Cell.Value, "'C:\")

我有2个简单的JS函数,一个检查2个输入字段的值并触发另一个函数这是代码

function ValidateForm()
    {
    var name = document.getElementById('fullname').value;
     var email = document.getElementById('email').value;
     if(name.value= '' || email.value='')
     {
     alert('fields Empty');
     }
     else
     {
     UpdateRecord();
     }

    }


    function UpdateRecord()
    {
    var Qact = getQueryVariable('ACT');
        if(Qact==2){

            var picture= document.getElementById('myPic').src;
            activity.setUpdates(name,email,picture);
            }
            else
            {
            activity.CheckEmail(name,email);
            }
        }

HTML

<button onClick="ValidateForm();" data-role="button" >Register</button>

如果我UpdateRecord()按下按钮点击它工作正常,但当我使用ValidateForm()没有任何作用.firefox调试器甚至没有转到ValidateForm()函数

我有当前的单元格名称,B7我希望将单元格的单元格名称设置为当前单元格,例如在这种情况下结果将是C7.我怎样才能实现这一点这就是我累了,但它不起作用

CellName = "B7"
ValueCellName = Right(Range(CellName)).name

我有一个样本詹森

[{"_2":["HR Data","Reformed (Master File)"]}]

我正在尝试将其反序列化为以下模型

public class ExploreCriteria
    {
        public Dictionary<String, List<String>> Explore { get; set; }
    }

这是我到目前为止尝试过的

ExploreCriteria Explore = new ExploreCriteria();
Explore = JsonConvert.DeserializeObject<ExploreCriteria>(JsonStr);

但它说

Cannot deserialize the current JSON array (e.g. [1,2,3]) into type
'DataModels.ExploreCriteria' because the type requires a JSON object
(e.g. {"name":"value"}) to deserialize correctly.

我将月份数作为整数,并希望将其转换为MMM格式这里是我尝试但它给我完整的月份名称

public String getMonth(int month) {
         return new DateFormatSymbols().getMonths()[month-1];
            }

它给了我April回报,但我想要Apr