小编Jim*_*son的帖子

(python)

so I have the following values & lists:

name = colour
size = ['256', '512', '1024', '2048', '4096', '8192', '16384', '32768']
depth = ['8', '16', '32']
scalar = ['False', 'True']
alpha = ['False', 'True']
colour = app.Color(0.5)

and I want to iterate over these to produce every possible combination with the following structure:

createChannel(ChannelInfo(name, size, depth, scalar, alpha, colour))

so the values for name, size, etc must stay in the same place, but they must iterate over all possible …

我试图使用<xs:unique>和<xs:key>/<xs:keyref>元素值,但我无法让它工作.如果我用attrubute值来做它就像魅力一样.

的test.xml

<test:config xmlns:test="http://www.example.org/Test"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.example.org/Test Test.xsd ">

    <test:location id="id1" path="/path2">
        <test:roles>
            <test:role>role1</test:role>
            <test:role>role2</test:role>
            <test:role>role2</test:role> <!-- DUPLICATE: FAIL VALIDATION  -->
        </test:roles>
        <test:action name="action1">
            <test:roles>
                <test:role>role1</test:role>
                <test:role>role1</test:role> <!-- DUPLICATE: FAIL VALIDATION -->
                <test:role>role3</test:role> <!-- NOT DEFINED: FAIL VALIDATION -->
            </test:roles>
        </test:action>
    </test:location>

</test:config>

我希望确保角色只定义一次,并且在action元素下定义的角色只是在上层定义的角色.

Test.xsd

<xs:element name="config">
    <xs:complexType>
        <xs:sequence>
            <xs:element ref="test:location" maxOccurs="unbounded" />
        </xs:sequence>
    </xs:complexType>       
</xs:element>

<xs:element name="location" type="test:LocationType">
    <xs:key name="keyRole">
        <xs:selector xpath="test:roles" />
        <xs:field xpath="test:role" />
    </xs:key>
    <xs:keyref …

嗨,我想使用XML文件作为配置文件,我将从中读取我的应用程序的参数.我遇到了PugiXML库,但是我遇到了获取属性值的问题.我的XML文件看起来像那样

<?xml version="1.0"?>
<settings>
    <deltaDistance> </deltaDistance>
    <deltaConvergence>0.25 </deltaConvergence> 
    <deltaMerging>1.0 </deltaMerging> 
    <m> 2</m>
    <multiplicativeFactor>0.7 </multiplicativeFactor> 
    <rhoGood> 0.7 </rhoGood>
    <rhoMin>0.3 </rhoMin>
    <rhoSelect>0.6 </rhoSelect>
    <stuckProbability>0.2 </stuckProbability> 
    <zoneOfInfluenceMin>2.25 </zoneOfInfluenceMin>
</settings>

要削减XML文件,我使用此代码

void ReadConfig(char* file)
{
    pugi::xml_document doc;
    if (!doc.load_file(file)) return false;

    pugi::xml_node tools = doc.child("settings");

    //[code_traverse_iter
    for (pugi::xml_node_iterator it = tools.begin(); it != tools.end(); ++it)
    {
        cout<<it->name() <<    " " <<    it->attribute(it->name()).as_double();  
    }

}

我也试图用这个

void ReadConfig(char* file)
{
    pugi::xml_document doc;
    if (!doc.load_file(file)) return false;

    pugi::xml_node tools = doc.child("settings");

    //[code_traverse_iter
    for (pugi::xml_node_iterator it = …

我在Java中执行SQL查询时遇到上述异常.

statement2.executeUpdate("INSERT INTO visit_header" 
    + "VALUES('"+visitnumber+"','"+date+"','"+cookie+"','"+ip+"')");

我想知道哪里出错了.

资料来源:https://discuss.leetcode.com/topic/28601/java-solutions-sorting-hashmap-moore-voting-bit-manipulation/2

问:确定数组中出现最多的元素.我能够解决它,但很想看别人的解决方案.所以我遇到了使用位操作的解决方案.

public int majorityElement(int[] nums) {
    int[] bit = new int[32];
    for (int num: nums)
        for (int i=0; i<32; i++) 
            if ((num>>(31-i) & 1) == 1)
                bit[i]++;
    int ret=0;
    for (int i=0; i<32; i++) {
        bit[i]=bit[i]>nums.length/2?1:0;
        ret += bit[i]*(1<<(31-i));
    }
    return ret;
}

当我更换线路

ret += bit[i]*(1<<(31-i)); 

同

ret += bit[i]*(1<<i);

我最终得到一个负数.

考虑输入数组 - [2,5,5,5,3],在第一个for循环之后,bit [0]将包含4,bit [1] = 2,bit [3] = 3,所有其他位将是0.

根据我的理解,第二个for循环将导致其位位置31和29设置为1的数字(与5不同).在我的理解中,我显然遗漏了一些东西.

有人可以解释这段代码是如何工作的？谢谢.

import java.util.*;

public class rearrange_palindrome {

    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        String st=sc.nextLine();

        ArrayList<Character> ar = new ArrayList<Character>();

        for (int i=0;i<st.length();i++){
            if (ar.contains(st.charAt(i)))
            ar.remove((Character)st.charAt(i));//why did they use type casting?
            else
            ar.add(st.charAt(i));
        }
        if (st.length()%2==0 && ar.isEmpty()==true || st.length()%2==1 && ar.size()==1)
        System.out.println("Palindrome");
        else
        System.out.println("Not a palindrome");
    }
}

请告诉我他们为什么使用类型转换的原因，我已经评论了该行。

我使用 org.springdoc 的依赖项，请参阅下面的 y spring boot 项目

       <dependency>
        <groupId>org.springdoc</groupId>
        <artifactId>springdoc-openapi-starter-webmvc-ui</artifactId>
        <version>2.0.2</version>
    </dependency>

我有这个错误，我可以帮忙吗？

    at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredMethodElement.resolveMethodArguments(AutowiredAnnotationBeanPostProcessor.java:759) ~[spring-beans-5.3.23.jar:5.3.23]
    ... 20 common frames omitted
Caused by: org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'indexPageTransformer' defined in class path resource [org/springdoc/webmvc/ui/SwaggerConfig.class]: Unsatisfied dependency expressed through method 'indexPageTransformer' parameter 3; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'swaggerWelcome' defined in class path resource [org/springdoc/webmvc/ui/SwaggerConfig.class]: Bean instantiation via factory method failed; nested exception is org.springframework.beans.BeanInstantiationException: Failed to instantiate [org.springdoc.webmvc.ui.SwaggerWelcomeWebMvc]: Factory method 'swaggerWelcome' threw exception; nested …

我正在写一个基于John Conway的生命游戏的程序.我得到它编译,甚至在经过几天不间断的工作后运行.但是,打印出来的结果是错误的......

这是我的代码(不包括主要方法)

 //clears the grid
public static void clearGrid ( boolean[][] grid )
{

    for(int row = 0; row < 18; row++){
       for(int col = 0; col < 18; col++){
          grid[row][col]= false;
       }
    }
    //set all index in array to false
}

//generate the next generation
public static void genNextGrid ( boolean[][] grid )
{
    int n; //number of neighbors

    boolean[][] TempGrid = grid;// a temporary array
    for(int row = 0; row < 18; row++)
    {
        for(int col = …

我编写了一个perl脚本,在其中调用子例程将字段插入数据库表.子例程在另一个文件Test.pm中调用,而不是主perl文件Test.pl. 在Test.pm中,我有以下字段要插入表中

my $date = localtime->strftime('%Y-%m-%d %H:%M:%S');
my $time = localtime->strftime('%H:%M:%S');

但是,在这里我得到以下错误

Can't locate object method "strftime" via package 

这是什么错误,为什么会发生这种错误.如果我传递$date和$time来自的参数Test.pl,脚本工作正常,我该如何解决？

以下是子程序:

sub send_message
{
     my $date = localtime->strftime('%Y-%m-%d %H:%M:%S');
     my $time = localtime->strftime('%H:%M:%S');
     print "Date : $date Time : $time";
     my $sql1 = "Insert into testtable(time,date) values('$time','$date')";
     my $sth1 = $dbh->prepare($sql1);
        $sth1->execute
        or die "SQL Error: $DBI::errstr\n";
     return;
}

我正在尝试在Java中实现BFS和DFS作为通用算法.我正在编写一种方法getComplexity(),将算法的最坏情况复杂性作为字符串返回.在DFS(和BFS)中,图中的每个节点只能访问一次.在最坏的情况下,每个节点只访问一次.因此,为什么这些算法的复杂性为O(V + E)而不是O(V)？这里V是节点(或顶点)的数量,E是边数.