继续在控制台中收到此错误"未捕获的ReferenceError:未定义谷歌".已经做了一段时间但没有运气.任何帮助非常感谢.提前致谢
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="initial-scale=1.0, user-scalable=no" />
<style type="text/css">
html { height: 100% }
body { height: 100%; margin: 0; padding: 0 }
#map-canvas { height: 100% }
</style>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"</script>
<script type="text/javascript"
src="https://maps.googleapis.com/maps/api/js?sensor=false">
</script>
<script type="text/javascript">
function initialize(location) {
console.log(location);
var mapOptions = {
center: new google.maps.LatLng(location.coords.latitude, location.coords.longitude),
zoom: 8
};
var map = new google.maps.Map(document.getElementById("map-canvas"),
mapOptions);
}
$(document).ready(function()
{
navigator.geolocation.getCurrentPosition(initialize);
});
</script>
</head>
<body>
<div id="map-canvas"/>
</body>
</html>
Run Code Online (Sandbox Code Playgroud) 接收变量时遇到问题,我收到的错误消息是
注意:未定义的索引:第7行的C:\ Users\PC\Documents\XAMPP\htdocs\php\addpost.php中的标题注意:未定义的索引:C:\ Users\PC\Documents\XAMPP\htdocs\php \中的文本第8行的addpost.php
// HTML文档
<div id="postdialog" title="Add Post" action="php/addpost.php">
<p>Please Fill in out member information.</p>
<form name="insertmember" action="php/addpost.php" >
<label>Title<input type="text" name="title" id="title"/></label>
<label>Text<textarea name="text"></textarea></label>
<input name="submit" type="submit" value="Submit" id="submit" />
</form>
</div>
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// PHP文件
if ($_POST['submit'] = "submit") {
$title = $_POST['title'];
$text = $_POST['text'];
$errors = array();
if (empty($_POST['title'])) {
$errors[] = "Title is Missing";
}
else
{
$title = $_POST['title']
if (strlen($fname) > 15 ) {
$errors[] = "Title is too long";
}
} …Run Code Online (Sandbox Code Playgroud) 我想查询数据库并从多行中提取检索信息,但我不确定MySQL语法.像这样的东西;
SELECT LastName FROM Users WHERE ID = 1 AND ID = 2 AND ID = 3
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所以我想收回来
Smith,Doe和Doe
Users
ID FirstName LastName
1 John Smith
2 Joe Doe
3 Jane Doe
More data etc etc
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