我已经在Android Studio中创建了一个项目,现在我想将该项目导入Eclipse,有将eclipse转换为Android Studio的选项,但是如何将Android studio转换为Eclipse?
在阅读了几个关于这个问题的问题和帖子后,我正在尝试旋转Zxing显示器.按照说明操作后,显示屏确实旋转,但扫描仪的矩形没有按照应有的位置放置(如附图所示).
这就是我所做的:
在CameraConfigurationManager中:
camera.setDisplayOrientation(90);
Run Code Online (Sandbox Code Playgroud)在DecodeHandler.java中
byte[] rotatedData = new byte[data.length];
for (int y = 0; y < height; y++) {
for (int x = 0; x < width; x++)
rotatedData[x * height + height - y - 1] = data[x + y * width];
}
int tmp = width;
width = height;
height = tmp;
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rect.left = rect.left * cameraResolution.y / screenResolution.x;
rect.right = rect.right * cameraResolution.y / screenResolution.x;
rect.top = rect.top * cameraResolution.x / screenResolution.y;
rect.bottom = rect.bottom …
Run Code Online (Sandbox Code Playgroud)我意识到这些依赖关系是编译Java servlet规范所必需的,等等,但我不清楚它们之间的区别,以及何时我应该使用一个而不是另一个.
他们之间有什么区别?是另一个的超集吗?
<dependency>
<groupId>javax</groupId>
<artifactId>javaee-api</artifactId>
<version>6.0</version>
<scope>provided</scope>
</dependency>
dependency>
<groupId>javax</groupId>
<artifactId>javaee-web-api</artifactId>
<version>6.0</version>
<scope>provided</scope>
</dependency>
Run Code Online (Sandbox Code Playgroud) 我在Listview中使用gridview,但我有一个可聚焦的问题.
我已经设置了gridview的宽度,但是我填写了gridview的一些项目,gridview的左侧空格(这是空白)表示未在listview中填充gridview的项目.如果我点击它,它不会执行listitem点击
如图像中所示,如果在列表项中的任何位置单击它,我想执行listview项单击.我想获得一个listitem点击.
但是,当我点击ListView
项目,即,GridView
则ListItem
点击是不工作...
public class History extends Activity {
String name, id, description, count, total;
ArrayList<String> TAG_ID = new ArrayList<String>();
ArrayList<String> TAG_COFFEESHOP_NAME = new ArrayList<String>();
ArrayList<String> TAG_COUNT = new ArrayList<String>();
ArrayList<String> TAG_TOTAL = new ArrayList<String>();
Context context;
JSONArray CoffeeUser = null;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.listlayout);
ListView listView = (ListView) findViewById(R.id.listnew);
listView.setAdapter(new MyCustomAdapter());
listView.setTextFilterEnabled(true);
listView.setOnItemClickListener(new AdapterView.OnItemClickListener()
{
public void onItemClick(AdapterView<?> paramAnonymousAdapterView, View paramAnonymousView, int paramAnonymousInt, long paramAnonymousLong)
{
Intent intent …
Run Code Online (Sandbox Code Playgroud) 我想在点击动态创建的图像时获取图像名称......
for(int i=0;i<list.size();i++)
{
final ImageButton b=new ImageButton(this);
LinearLayout.LayoutParams layoutParams = new LinearLayout.LayoutParams(70, 70);
layoutParams.setMargins(5, 5, 0, 0); // left, top, right, bottom
b.setLayoutParams(layoutParams);
Resources res = getResources();
int resourceId = res.getIdentifier("_"+list.get(i).toString(), "drawable", getPackageName() );
b.setImageResource( resourceId );
b.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
//at here i want to get the selected image name
}
});
rowoptions.addView(b);
}
Run Code Online (Sandbox Code Playgroud) 我搜索了很多东西: 如何在谷歌地图上显示图标闪烁
但根据这个我没有找到如何闪烁通知图标闪烁
我想在这上面闪烁图标
int icon = R.drawable.ic_launcher;
long when = System.currentTimeMillis();
notificationManager = (NotificationManager) context
.getSystemService(Context.NOTIFICATION_SERVICE);
Notification notification = new Notification(icon, "Hi M rohit", when);
String title = context.getString(R.string.app_name);
Intent notificationIntent = new Intent(context, Home.class);
// set intent so it does not start a new activity
notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);
PendingIntent intent = PendingIntent.getActivity(context, 0, notificationIntent, 0);
notification.setLatestEventInfo(context, title, "Rohit", intent);
//notification.flags |= Notification.FLAG_AUTO_CANCEL;
notification.flags |= Notification.FLAG_SHOW_LIGHTS;
notification.flags |= Notification.FLAG_NO_CLEAR;
notification.defaults = Notification.DEFAULT_ALL;
notificationManager.notify(NOTIFICATION, notification);
Run Code Online (Sandbox Code Playgroud) 我有以下ng-repeat
代码:
<li ng-repeat="vid in vids | filter:query | orderBy:orderProp">
{{vid.title}}
</li>
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我的问题是,如果我不知道密钥名称,我可以循环访问vid并打印出每个密钥和值吗?
那么我将如何在PHP中做到这一点:
<?php
foreach ($vids as $key => $val) {
echo $key . "=" . $val;
}
?>
Run Code Online (Sandbox Code Playgroud) 我想防止清除共享首选项或数据库,以便仅在卸载应用程序时清除。如何在应用程序上确保共享首选项的安全。明确?
http://www.jetbrains.com/idea/docs/IntelliJIDEA_ReferenceCard.pdf
如同我们在Eclipse中按"ctrl + alt + f"然后所有文本自动格式化.怎么在ubuntu?
如果我们在ubuntu上使用CTL + ALT + L,那么它会关闭logg
怎么在Android Studio ubuntu?
我设置了搜索栏的属性.它达到一个过程,但其过程未达到1,如下图所示
sbpassangers.setProgress(1); //set this at onCreate
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xml:
<SeekBar
android:id="@+id/sBpassangers"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_alignParentTop="true"
android:layout_toLeftOf="@+id/tvPassengers"
android:layout_toRightOf="@+id/ivPhone"
android:layout_weight="2"
android:paddingBottom="3dp"
android:paddingLeft="2dp"
android:paddingTop="3dp" />
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java代码:
sbpassangers.setProgress(1);
sbpassangers.setMax(sb1.getProgress());
tvtaxipassangers.setText(Integer.toString(1));
//sb1.setMax(9);
//sb1.setProgress(2); // Set it to zero so it will start at the left-most edge
sbpassangers.setOnSeekBarChangeListener(new OnSeekBarChangeListener() {
@Override
public void onProgressChanged(SeekBar seekBar, int progress, boolean fromUser) {
seekBar.setProgress(progress);
if(progress == 0){
seekBar.setProgress(1);
}
tvtaxipassangers.setText(Integer.toString(seekBar.getProgress()));
}
@Override
public void onStartTrackingTouch(SeekBar seekBar) {}
@Override
public void onStopTrackingTouch(SeekBar seekBar) {}
});
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应该是这样的:
请帮忙解决这个问题