小编app*_*y g的帖子

我一直收到以下错误.

com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: 
You have an error in your SQL syntax; check
the manual that corresponds to your MySQL server version for 
the right syntax to use near '= 3' at line 1

我浏览了整个代码,此时只有2个SQL函数被调用,能够导致此错误:

1. 读

   public void Read (String userName) /*have checked validity*/
   try {
       con = getConnection();
   
       PreparedStatement pstmt = con.prepareStatement("SELECT * FROM " + 
                                 tableName + 
                                " WHERE userName=?");
   
           pstmt.setString(1,userName);
   
       ResultSet rs = pstmt.executeQuery();
   
       User user;
       PrintQuery(rs);
       rs.close();
       pstmt.close();
       releaseConnection(con);
       return user;
   
   }
   

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2. 的GetItem

    public void getItem(int userid) /*have …

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这是导致此错误的代码.

发送线程:

 data = pickle.dumps (object);

接收线程:

 self.object = pickle.loads(data) // Erroneous line

显示的错误是

    self.object = pickle.loads(data)
EOFError

此外,为了添加细节,此错误仅发生50%的次数.其他50%的时间,没有错误!