我是初学者,我有一个需要帮助的问题.它是功课,所以任何提示都受到赞赏.我看过一些类似的话题,但答案超出了我所知道的怎么做......
我需要计算文本文件中音节的数量,作为更大程序的一部分.除了音节,我有我需要的一切.我尝试了几种不同的方法,但它并不总能捕捉特殊情况.我应该'计算相邻元音的组,不包括单词末尾的'e'.我明白这意味着什么,但我无法在我的计划中做到这一点.这是我的:::
def syllables(word):
syl = 0
vowels = 'aeiouy'
starts = ['ou','ei','ae','ea','eu','oi']
endings = ['es','ed','e']
word = word.lower().strip(".:;?!")
for vowel in vowels:
syl +=word.count(vowel)
for ending in endings:
if word.endswith(ending):
syl -=1
for start in starts:
if word.startswith(start):
syl -=1
if word.endswith('le'):
syl +=1
if syl == 0:
syl+=1
return syl
编辑:新代码
def syllables(word):
count = 0
vowels = 'aeiouy'
word = word.lower().strip(".:;?!")
if word[0] in vowels:
count +=1
for index in range(1,len(word)):
if word[index] in vowels and word[index-1] …我是Python新手，我有一个问题。有人告诉我要问这个问题，与我为同一程序编写的另一个帖子分开问。这是家庭作业，所以我只需要一些指导。我有一个元组列表，我想按tuple [0]对其进行排序，然后将要打印的完整元组返回到屏幕。元组由（得分，标记（x或o），索引）组成
这是我的基本代码（井字游戏的一部分-我在另一篇文章中有完整代码）：::
listOfScores = miniMax(gameBoard)
best = max(listOfScores, key=lambda x: x[0])
if best[0] == 0:
print("You should mark " + best[1] + " in cell " + best[2] + ".")
print("This will lead to a tie.")
elif best[0] > 0:
print("You should mark " + best[1] + " in cell " + best[2] + ".")
print("This will lead to a win.")
else:
print("You should mark " + best[1] + " in cell " + best[2] + ".")
print("This will …我遇到了这个错误的严重问题.这是家庭作业,所以我只是在寻找一些关于这个的提示...我已经看了其他问题,但他们没有帮助,所以希望这没关系.我是Python的新手.:)我正在做一个Tic Tac Toe游戏.我确信它还有其他一些问题,但我现在主要担心的是这个错误.这是我的代码:::
scoreList = []
"""keeps track of all of the scores, moves, and indexes as tuples for each
winning board"""
def getEmptySpaces(gameBoard):
return gameBoard.count('-')
def winner(gameBoard):
case1 = gameBoard[0]+gameBoard[1]+gameBoard[2]
case2 = gameBoard[0]+gameBoard[3]+gameBoard[6]
case3 = gameBoard[0]+gameBoard[4]+gameBoard[8]
case4 = gameBoard[1]+gameBoard[4]+gameBoard[7]
case5 = gameBoard[2]+gameBoard[5]+gameBoard[8]
case6 = gameBoard[2]+gameBoard[4]+gameBoard[6]
case7 = gameBoard[3]+gameBoard[4]+gameBoard[5]
case8 = gameBoard[6]+gameBoard[7]+gameBoard[8]
if case1 == 'xxx' or case1 == 'ooo':
return True
elif case2 == 'xxx' or case2 == 'ooo':
return True
elif case3 == 'xxx' or case3 == 'ooo': …