小编D18*_*180的帖子

每次我必须转换int成String我选择的一个""+a或Integer.toString(a).现在我想知道哪种方式更快,所以我编写了一个简单的基准测试,调用function_1,function_2和function_3 10000000次并打印处理函数所需的时间.以下是功能:

public static String i="";
public static String j="";
public static String k="";

public static void function_1()
{
    i=Integer.toString(getOne());
}

public static void function_2()
{
    j=""+1;
}

public static void function_3()
{
    j=""+getOne();
}

public static int getOne()
{
    return 1;
}

输出是:

Benchmarking starting...
Executing function_1 10000000 time(s)...
Done executing function_1 in 476 ms.
Executing function_2 10000000 time(s)...
Done executing function_2 in 8 ms.
Executing function_3 10000000 time(s)...
Done executing …

我有程序,我必须加载PNG作为字符串,然后再次保存,但在我保存后,它变得不可读.如果我在编辑器中打开加载的PNG和保存的字符串,我可以看到java在整个文件中创建了换行符.如果这是问题所在,我该如何避免这种情况？

    public static void main(String[] args)
    {
        try
        {
            File file1 = new File("C://andim//testFile.png");
            StringBuffer content = new StringBuffer();
            BufferedReader reader = null;
            reader = new BufferedReader(new FileReader(file1));
            String s = null;         
            while ((s = reader.readLine()) != null) 
            {
                content.append(s).append(System.getProperty("line.separator"));                      
            }
            reader.close();
            String loaded=content.toString();
            File file2=new File("C://andim//testString.png");
            FileWriter filewriter = new FileWriter(file2);
            filewriter.write(loaded);           
            filewriter.flush();
            filewriter.close();
        }
        catch(Exception exception)
        {
            exception.printStackTrace();
        }

    }