由于某种原因,gradle没有运行我的测试.当我执行时gradle cleanTest test -i我得到:
Skipping task ':compileJava' as it is up-to-date (took 0.262 secs).
:compileJava UP-TO-DATE
:compileJava (Thread[main,5,main]) completed. Took 0.266 secs.
:processResources (Thread[main,5,main]) started.
:processResources
Skipping task ':processResources' as it has no source files.
:processResources UP-TO-DATE
:processResources (Thread[main,5,main]) completed. Took 0.001 secs.
:classes (Thread[main,5,main]) started.
:classes
Skipping task ':classes' as it has no actions.
:classes UP-TO-DATE
:classes (Thread[main,5,main]) completed. Took 0.0 secs.
:compileTestJava (Thread[main,5,main]) started.
:compileTestJava
Skipping task ':compileTestJava' as it has no source files.
:compileTestJava UP-TO-DATE …我有一个文件,其中包含以下文字:
text
START
This
has
to
be
printed
STOP
more text
现在我希望打印START和STOP之间的文本.我写了以下内容:
cat file | sed '/START/,/STOP/p'
但这似乎并没有做我想要的.有什么建议？
我有一个简单的函数来计算下面的第n个fibonnaci数:
fibonacci :: Integer -> Integer
fibonacci 0 = 0
fibonacci 1 = 1
fibonacci n = (fibonacci (n-1) ) + (fibonacci (n-2))
但我感兴趣的是计算此函数的递归数量的方法.有什么想法怎么做？
我quickcheck为一个优化和评估函数的Haskell程序编写了测试.
问题是quickcheck生成表达式,结果NaN如下:
> acos(2)
NaN
Haskell将以下语句评估为false:
> acos(2)==acos(2)
False
所以我的quickcheck测试因这种比较而失败.有没有办法比较NaN价值观？
我正在尝试比较序言中的两个列表，例如
?- compare([[X],Y,Z],[[A],B,C]).
true.
?- compare([X,Y,Z],[[A],B,C]).
false.
我不能使用 ==/2 运算符，因为逻辑变量不相同，因此这两种情况都会评估为 false。而且我显然不能使用 =/2 因为这在两种情况下都会评估为真。
有关如何解决此问题的任何建议？