在试图弄清楚如何将.NET System.ServiceModel.Channels.Message对象转换为XmlDocument时,我想我可以这样做:
Message message = Message.CreateMessage(messageVersion, "SOAPAction");
using(var messageBuffer = message.CreateBufferedCopy(int.MaxValue))
{
var stream = new MemoryStream();
using(var xmlWriter = XmlWriter.Create(stream))
{
var xmlDocument = new XmlDocument();
messageBuffer.WriteMessage(stream);
stream.Flush();
stream.Position = 0;
xmlDocument.Load(stream);
stream.Close();
Debug.Writeline(xmlDocument.OuterXml);
}
}
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但是,这会导致xmlDocument.Load(stream)出错:
"Data at the root level is invalid. Line 1, position 1."
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我现在意识到我应该使用Message对象的WriteMessage与XmlWriter对象一起使用,如下所示:
Message message = Message.CreateMessage(messageVersion, "SOAPAction");
using(var messageBuffer = message.CreateBufferedCopy(int.MaxValue))
{
var stream = new MemoryStream();
using(var xmlWriter = XmlWriter.Create(stream))
{
var xmlDocument = new XmlDocument();
messageBuffer.CreateMessage().WriteMessage(xmlWriter);
xmlWriter.Flush();
stream.Flush();
stream.Position = …Run Code Online (Sandbox Code Playgroud) 我正在使用的api需要使用的设备的型号名称.在Windows 8中我会使用Microsoft.Phone.Info.DeviceStatus.DeviceName.但是,我在Windows 8.1中创建了一个新的通用应用程序,并且"Microsoft.Phone"命名空间似乎缺失了.
如何在Windows 8.1中找到与通用应用程序一起使用的设备的型号名称