小编use*_*367的帖子

使用Sass进行导航.我正在尝试使用:最后一个子选择器为最后一个菜单链接应用不同的链接颜色(红色)但没有成功.任何人都可以告诉我如何从以下Sass代码实现？下面是我到目前为止的代码.任何建议将不胜感激!

HTML

<ul class="menu">
   <li>
       My Navigation
   </li>
   <li>
       <a href="#">First Link</a>
   </li>
   <li>
       <a href="#">Second Link</a>
   </li>
   <li>
       <a href="#">Third Link</a>
  </li>
</ul>

萨斯

.menu {
    @include inline-list;
    font-size: 13px;


    &, a {
        color: black;
        text-decoration: none;

    }
    > * + * {
        margin-left: .5em;

        + *:before {
            content: ">";
            margin-right: .5em;
        }
    }

    & a ul li:last-child {
        color: red;
        font-weight: bold;
    }
}

我正在为DotNetNuke的DDR Treeview菜单工作,只显示所选的Root项及其要扩展的子节点.这是我想要实现的目标.(左垂直菜单)有什么建议吗？

这是xslt代码,目前显示所有根项.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="html"/>
  <xsl:param name="ControlID" />
  <xsl:param name="Options" />
  <xsl:template match="/*">
    <xsl:apply-templates select="root" />
  </xsl:template>
  <xsl:template match="root">
    <xsl:if test="node">
      <ul class="treeview filetree" id="{$ControlID}">
        <xsl:apply-templates select="node" />
      </ul>
      <script type="text/javascript">
        jQuery(function($) {
          $("#<xsl:value-of select="$ControlID" />").treeview(
            <xsl:value-of select="$Options" disable-output-escaping="yes" />
          );
        });
      </script>
    </xsl:if>
  </xsl:template>
  <xsl:template match="node">
    <li>
      <xsl:if test="node and (@depth != 0 or @breadcrumb = 1)">
        <xsl:attribute name="class">open</xsl:attribute>
      </xsl:if>
      <xsl:choose>
        <xsl:when test="@enabled = 0">
          <xsl:value-of select="@text" />
        </xsl:when>
        <xsl:otherwise>
          <a href="{@url}">
            <xsl:choose> …

嗨,我正在尝试在一个活动中创建多个上下文菜单.有两个按钮,我想为每个按钮创建不同的上下文菜单.有人可以建议我或推荐我一些有用的例子吗？

这是我目前的代码.

registerForContextMenu(btn_1);
registerForContextMenu(btn_2);


btn_1.setOnClickListener(new View.OnClickListener() {

    public void onClick(View v) {

        openContextMenu(v);
    }   
});

btn_2.setOnClickListener(new View.OnClickListener() {

    public void onClick(View v) {

        openContextMenu(v);
    }   

});


    }

@Override
public void onCreateContextMenu(ContextMenu menu, View v,ContextMenu.ContextMenuInfo menuInfo) {
        super.onCreateContextMenu(menu, v, menuInfo);
        getMenuInflater().inflate(R.menu.media_menu, menu);
        menu.setHeaderTitle("Context menu for btn_1");
        menu.setHeaderIcon(R.drawable.icon_media_up); 
}

@Override
public boolean onContextItemSelected(MenuItem item) {
        switch(item.getItemId()) {
            case R.id.photo:
                Toast.makeText(this, "One", Toast.LENGTH_SHORT).show();
                return true;
            case R.id.video:
                Toast.makeText(this, "Two", Toast.LENGTH_SHORT).show();
                return true;
            case R.id.audio:
                Toast.makeText(this, "Three", Toast.LENGTH_SHORT).show();
                return true;
            }
        return super.onContextItemSelected(item);
    }

我不确定我做错了什么但是在为#content应用背景颜色时遇到了麻烦.但是如果我将高度值设置为800px就行了.但我希望它是自动或100%,因为这个模板将在整个网站中使用.任何建议将不胜感激.

<div class="content_bg">
    <div id="content">
        <div id="contentLeft">   
        </div>
        <div id="contentRight"> 
            <div id="ContentPane" runat="server" />           
        </div>
    </div>
</div>
<div class="footer_bg">
    <div id="footer">
        <div id="footerLeft">            
        </div>
        <div id="footerRight">           
        </div>
    </div>
</div>

/*
====================================================================
Content Area
====================================================================
*/

.content_bg
{
    background:#dadad9 url(images/interior_content_bg_top.jpg) repeat-x center top;
    overflow:hidden;
}

#content
{
    width:980px;
    margin:auto; 
    height:auto; 
    background:#fff; 

}

#contentLeft
{
    float:left;
    width:209px; 
    margin-top:50px;   
}


#contentRight
{
    float:right;
    width:770px; 
    margin:20px 0 0 0;
}

/*
====================================================================
Footer
====================================================================
*/

.footer_bg
{
    background:#dadad9 url(images/interior_footer_bg.jpg) repeat-x center top;
    clear:both;
} …

嗨,我正在使用ImageButton点击活动,但它无法完成当前活动.

btn_home.setOnClickListener(new View.OnClickListener() {

            public void onClick(View view) {

                Intent i = new Intent(getApplicationContext(), GridActivity.class);
                i.putExtra("feed", _rssFeed);
                startActivity(i);

                SwipeDetailView.this.finish();
            }
        }); 

但是,如果我单击同一类中操作栏菜单上的主页按钮,它会正常关闭.

public boolean onOptionsItemSelected(MenuItem item) {
    switch (item.getItemId()) {

    case android.R.id.home:

        finish();
        return true;
    }
    return super.onOptionsItemSelected(item);
}

我正在尝试通过发出HTTP请求更新Android中的MySQL数据,但它给了我一个错误

"类型不匹配:无法从org.apache.http.HttpResponse转换为com.google.api.client.http.HttpResponse"

在这行代码"httpClient.execute(httpPost)"

HttpResponse response = httpClient.execute(httpPost);

它通过添加org.apache.http来提供快速修复的选项

org.apache.http.HttpResponse response = httpClient.execute(httpPost);

有人能告诉我这里我做错了什么吗？非常感谢!

protected String doInBackground(String... params) {

    HttpClient httpClient = new DefaultHttpClient();
    HttpPost httpPost = new HttpPost("http://---.com/---/approve_request.php");

    List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>();
    nameValuePair.add(new BasicNameValuePair("status", "Approved"));

    try {
          httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair));
        } catch (UnsupportedEncodingException e) {              
           e.printStackTrace();
        }

           try {
              org.apache.http.HttpResponse response = httpClient.execute(httpPost);  
              Log.d("Http Response:", response.toString());

         } catch (ClientProtocolException e) {             
              e.printStackTrace();

         } catch (IOException e) {              
              e.printStackTrace();

         }

    return null;
    }