小编Umu*_*nan的帖子

我需要获得可拖动面板的下降位置.但我无法弄清楚如何做到这一点.我试图获得这种风格,但我得到了无关的信息.

这是我的xhtml:

<h:form id="dnd">

   <p:panel id="draggable1" 
            style="z-index:1; width: 60px; height: 60px;">
       <h:outputText value="CAM-1" />
       <p:draggable for="draggable1" 
                    revert ="false"/>
   </p:panel>

   <p:panel id="droppable" 
            style="z-index:1; width: 600px; height: 600px;">
      <p:droppable for="droppable"> 
          <p:ajax listener="#{myBean.onDrop}" />
      </p:droppable>
   </p:panel>

</h:form>

这是我的支持bean:

public void onDrop(DragDropEvent dragDropEvent) {
    String dragId = dragDropEvent.getDragId();

    UIComponent draggedItem = FacesContext.getCurrentInstance().getViewRoot().findComponent(dragId);

    System.out.println(draggedItem.getClientId());
    Panel draggedPanel = (Panel) draggedItem;

    String style = draggedPanel.getStyle();
    System.out.println(style);

    String styleClass = draggedPanel.getStyleClass();
    System.out.println(styleClass);
}

任何帮助将不胜感激.提前致谢.