小编Rob*_*Rob的帖子

如何将此输出转换为字符串？

List<string> Client = new List<string>();
foreach (string listitem in lbClients.SelectedItems)
{
    Client.Add(listitem);
}

对不起新手问题.有人可以帮帮我吗？这里有简单的数组 检查所有用户输入的最佳/最简单方法是唯一且不重复的？谢谢

    private void btnNext_Click(object sender, EventArgs e)
    {

        string[] Numbers = new string[5];


        Numbers[0] = txtNumber1.Text;
        Numbers[1] = txtNumber2.Text;
        Numbers[2] = txtNumber3.Text;
        Numbers[3] = txtNumber4.Text;
        Numbers[4] = txtNumber5.Text;


        foreach (string Result in Numbers)
        {
            lbNumbers.Items.Add(Result);
        }

        txtNumber1.Clear();
        txtNumber2.Clear();
        txtNumber3.Clear();
        txtNumber4.Clear();
        txtNumber5.Clear();
    }
}

}

我应该补充一下,我需要在输出数字之前检查一下.谢谢

我正在尝试创建代码以将wav文件放入数组列表,然后让arraylist播放文件.为什么这段代码不起作用？谢谢.

public class trackList {

    public void tracklist(){

        ArrayList<String> songs = new ArrayList();
        songs.add("c:\\01.wav");
        songs.add("c:\\02.wav");

        byte[] buffer = new byte[4096];
        for(int x = 0; x < songs.size(); x++){

          try{

                AudioInputStream ais = AudioSystem.getAudioInputStream(songs(x));
                AudioFormat format = ais.getFormat();
                SourceDataLine line = AudioSystem.getSourceDataLine(format);
                line.open(format);
                line.start();

          while (ais.available() > 0) {

                int len = ais.read(buffer);
                line.write(buffer, 0, len);

               }

            line.drain(); 
            line.close();

                } 
          catch (Exception e) {

                e.printStackTrace();

                }
        }                       
    } 
}