小编nie*_*lsv的帖子

Vimeo全宽

我正在尝试在网页中显示全宽的vimeo视频.

这就是它现在的样子:

你可以看到黑色是全宽而不是视频.它应该是全宽,没有显示控件,自动播放和循环播放.

我的代码现在看起来像这样:

<iframe src="https://player.vimeo.com/video/208176323?autoplay=1&loop=1&background=1" width="100%" height="500px" frameborder="0" webkitallowfullscreen mozallowfullscreen allowfullscreen></iframe>

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客户端有vimeo plus但不是vimeo pro.有人可以帮我弄这个吗.

更新:

我已将代码更改为:

<style>
    .embed-container {
        position: relative;
        padding-bottom: 56.25%;
        height: 0; overflow: hidden;
        max-width: 100%; height: auto;
    }
    .embed-container iframe, .embed-container object, .embed-container embed {
        position: absolute;
        top: 0;
        left: 0;
        width: 100%;
        height: 100%;
    }
</style>

<div class='embed-container'><iframe src='https://player.vimeo.com/video/208791851?autoplay=1&loop=1&background=1' frameborder='0' webkitAllowFullScreen mozallowfullscreen allowFullScreen></iframe></div>

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但我仍然在底部和顶部有黑色边框.

我已经创建了一个jsfiddle,你也可以看到这个:https://jsfiddle.net/07fkfwz3/ .你在这里看到的视频没有任何边框.

html css video vimeo width

nie*_*lsv

2017 03-17

15
推荐指数

3
解决办法

3万
查看次数

复合标识符,但使用除手动分配+ Symfony2之外的ID生成器

我有三张桌子.

item 与领域

    PK id
    title
    description
    type
    created
    delete
    fk user_id

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article 与领域

    PK item_id (one-to-one with item table), 
    body

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media 与领域

    PK id
    FK item_id (many-to-one with item table)
    url
    type
    mimetype
    isexternal

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表中的type字段article是带有值的ENUM ITEM, ARTICLE and IMAGE.
实体是自动生成的.因此,最初文章实体不会扩展项目实体.我不得不改变这一点.

我总是得到这个错误:

Entity 'Beachteam\BeachteamBundle\Entity\Article' has a composite identifier 
but uses an ID generator other than manually assigning (Identity, Sequence). 
This is not supported.

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更新:
删除我的类型变量并修复discriminatormap后,我收到此错误:

Property Beachteam\BeachteamBundle\Entity\Item::$type does not exist

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这是我更新的物品实体:

<?php

namespace Beachteam\BeachteamBundle\Entity;

use …

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php mysql sql symfony doctrine-orm

nie*_*lsv

2014 02-27

14
推荐指数

1
解决办法

2862
查看次数

在其他div旁边滚动div

我有这样的布局:

滚动到底部时,左列应向下滚动(直到下一个类别).

我的HTML看起来像这样:

    <div class="wrapper gray-bg">
   <div class="centered">
      <div class="row">
         <div class="col-xs-12 col-sm-12 col-md-5 col-lg-4 information group">
            <h1>Glas</h1>
            <hr>
            <p class="info">
            </p>
            <p>Wil je een maximale <strong>lichtinval</strong> en maximale <strong>isolatie</strong>, maar hou je ook van een <strong>strak design</strong>?&nbsp;Kies dan voor onze vlakke lichtkoepels met dubbelwandig of 3-dubbel glas. Ze zien er niet alleen geweldig uit, maar scoren op alle vlakken ongelooflijk goed.</p>
            <p></p>
            <div class="buttons">
               <a href="" class="button">bekijk referenties</a>
               <a href="/nl/professional/contact" class="button gray">Vraag offerte</a>
            </div>
         </div>
         <div class="col col-xs-12 col-sm-12 …

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html javascript css jquery

nie*_*lsv

lucky-day

14
推荐指数

1
解决办法

494
查看次数

将类stdClass的Object转换为JSON Object

这是我的PHP文件中的内容:

$session = $m->session;

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$ session现在是:

object(stdClass)[31]
  public 'id' => string '21112' (length=5)
  public 'external_id' => string '' (length=0)
  public 'sessiongroupid' => string '1843' (length=4)
  public 'eventid' => string '5588' (length=4)
  public 'order' => string '0' (length=1)
  public 'name' => string 'Ferdau Conference' (length=17)
  public 'description' => string 'Ferdau Conference' (length=17)
  public 'starttime' => string '2013-04-18 18:00:00' (length=19)
  public 'endtime' => string '2013-04-18 18:04:00' (length=19)
  public 'speaker' => string '' (length=0)
  public 'location' => string 'Waregem' (length=7)
  public 'mapid' => …

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javascript php json converter object

nie*_*lsv

2013 04-17

12
推荐指数

1
解决办法

3万
查看次数

地理定位的结果箭头(角度)不正确

我有一个关于向某个位置显示箭头的问题.这就是我所拥有的: 在此输入图像描述

您可以将当前位置保存在本地存储中.不久之后,当您再进一步30米时,您可以点击第二个按钮"向前一个位置显示方向!" 获得箭头到您以前的位置.这是一个移动网站,因此不是本机应用.

这是我的代码:

<!DOCTYPE html>
<html>
    <head> 
        <!-- JQUERY SCRIPT AND COMPASS SCRIPT AND MODERNIZR SCRIPT -->
        <script src="http://code.jquery.com/jquery-1.8.3.js"></script>      
    </head>
    <body>
        <div class="container">
            <h1>Find your location</h1>
            <div class="row">
                <div class="span12">
                    <!-- Save your current location -->
                    <button class="grey" id="btnFindLocation">Save my current location!</button> <br>
                    <!-- Show direction to previous location -->
                    <button class="grey" id="btnShowDirection">Show direction to previous location!</button> <br><br>

                    <!-- Arrow in direction to location -->
                    <img id="myarrow" class="deviceorientation" src="http://nielsvroman.be/tapcrowd/arrow.png" />
            </div>
        </div>
        <script>
        $(window).ready(function(){
            // orientation object to save …

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javascript jquery geolocation heading device-orientation

nie*_*lsv

lucky-day

11
推荐指数

1
解决办法

776
查看次数

Laravel Omnipay - 需要transactionReference参数

我正在使用名为Attendize的开源票证系统.

他们已经将支付提供商Stripe集成在一起.现在我正在尝试与支付提供商Mollie合作.

问题是我一直在绊倒这个错误:

我的代码看起来像这样:

$transaction_data += [
    'transactionId' => $event_id . date('YmdHis'),
    'returnUrl' => route('showEventCheckoutPaymentReturn', [
        'event_id'              => $event_id,
        'is_payment_successful' => 1
    ]),
];

$apiKey = "test_gSDS4xNA96AfNmmdwB3fAA47******";
$gateway->setApiKey($apiKey);


$transaction = $gateway->purchase($transaction_data);

$response = $transaction->send();

if ($response->isSuccessful()) {

    session()->push('ticket_order_' . $event_id . '.transaction_id',
        $response->getTransactionReference());

    return $this->completeOrder($event_id);

} elseif ($response->isRedirect()) {
    /*
     * As we're going off-site for payment we need to store some data in a session so it's available
     * when we return
     */ …

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php payment-gateway laravel omnipay mollie

nie*_*lsv

2017 07-11

11
推荐指数

1
解决办法

696
查看次数

ASP.NET MVC +填充下拉列表

在我的viewModel中我有:

public class PersonViewModel
{
    public Person Person { get; set; }
    public int SelectRegionId { get; set; }
    public IEnumerable<SelectListItem> Regions { get; set; }
}

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但是我在Controller/View中需要做些什么来显示值？我现在拥有的:
控制器:

public ActionResult Create()
{
     var model = new ReUzze.Models.PersonViewModel
     {
         Person = new Person(),
         Regions = new SelectList(this.UnitOfWork.RegionRepository.Get(), "Id", "Name")
     };
     return View(model);
}

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视图:

 <div class="form-group">
     @Html.LabelFor(model => model.Person.Address.Region)
     @Html.DropDownListFor(model => model.SelectRegionId, new SelectList(Model.Regions, "Id", "Name"), "Choose... ")
 </div>

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但它给出了这样的错误:

Cannot implicitly convert type 'System.Web.Mvc.SelectList' to 'System.Collections.Generic.IEnumerable<System.Web.WebPages.Html.SelectListItem>'. An explicit conversion …

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c# asp.net asp.net-mvc html.dropdownlistfor asp.net-mvc-4

nie*_*lsv

2013 12-13

10
推荐指数

2
解决办法

4万
查看次数

可捕获的致命错误:传递给...的参数1必须是...,给定数组的实例

我想注册一个用户.在我的数据库中,我有一个user带有FK 的表,player_id在我的玩家表中team_id,我的团队表中有一个FK .

这是我的RegisterType表单:

class RegisterType extends AbstractType
{
    /**
     * @param FormBuilderInterface $builder
     * @param array $options
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('userFirstname', 'text', [
                'label' => 'Given name*',
                'attr'  => [
                    'placeholder' => 'Enter your given name.',
                ],
            ])
            ->add('userSurname', 'text', [
                'label' => 'Family name*',
                'attr'  => ['placeholder' => 'Enter your family name.'],
            ])
            ->add('userType', 'choice', array(
                'choices' => array('E' => 'ENTHOUSIAST', 'P' => 'PLAYER', 'T' => …

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php arrays entity doctrine symfony

nie*_*lsv

2014 01-11

10
推荐指数

1
解决办法

4万
查看次数

LOAD DATA INFILE + MySQL错误28000

我遇到了以下要执行的SQL查询的问题:

LOAD DATA INFILE 'thelocationofmyfile.csv'
INTO TABLE test_import 
FIELDS TERMINATED BY ';'
LINES TERMINATED BY '\r\n'
IGNORE 1 LINES ( ArtID, ArtNamePharmLang, ArtNameFr, ArtNameNl, PubPrice, PercentageRebate, RebateAmount, SellingPrice, Localisation, CnkNr, EanNr, SoldQty, MinThd, MaxThd, QtyInStock, DateLastSale, VatRate, SupplierManufName, BuyPrice, InvCatCode, ArtType, ApbCatCode, ApbLegCode, PharmApbNr );

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我想将excel文件的数据加载到我的数据库中的表中.当我在本地运行时一切正常.但是当我在服务器上执行此操作时,我收到以下错误:

Uncaught exception 'PDOException' with message 'SQLSTATE[28000]: Invalid authorization specification: 1045 Access denied for user 'myuser'@'localhost' (using password: YES)'

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我正在尝试用PHP(在Zend Framework中)这样做.当我联系托管时,他们说我需要FILE权限才能执行此操作.但这是不好的做法,并没有提出建议.

我也尝试在这样的shell脚本中执行此操作:

#!/bin/bash
/usr/bin/mysql --host=localhost --user=theuser --password=password --database=db_database<<EOFMYSQL
LOAD DATA INFILE 'locationofmyfile.csv'
INTO …

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php mysql sql csv permissions

nie*_*lsv

2015 11-16

10
推荐指数

1
解决办法

1728
查看次数

Amazon S3 - 您建议的上传小于允许的最小大小

当我想将图像上传到我的亚马逊s3水桶时,我遇到了问题.

我正在尝试上传大小为238 KB的jpg图像.我在我的代码中放了一个try/catch来检查错误是什么.我总是得到这个错误:

您建议的上传量小于允许的最小尺寸

我也用1MB和2MB的图像试过这个,同样的错误....

这是我的代码:

<?php

// Include the SDK using the Composer autoloader
require 'AWSSDKforPHP/aws.phar';

use Aws\S3\S3Client;
use Aws\Common\Enum\Size;

$bucket = 'mybucketname';
$keyname = 'images';
$filename = 'thelinktomyimage';

// Instantiate the S3 client with your AWS credentials and desired AWS region
$client = S3Client::factory(array(
    'key'    => 'key',
    'secret' => 'secretkey',
));


// Create a new multipart upload and get the upload ID.
$response = $client->createMultipartUpload(array(
    'Bucket' => $bucket,
    'Key'    => $keyname
));

$uploadId = $response['UploadId'];

// 3. Upload …

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php file-upload amazon-s3 minimum-size amazon-web-services

nie*_*lsv

2013 10-15

9
推荐指数

2
解决办法

1万
查看次数