小编Pra*_*ane的帖子

目前我正在开发 PySpark 和 DataFrame。
我创建了一个数据框：

from pyspark.sql import *
import pandas as pd
spark = SparkSession.builder.appName("DataFarme").getOrCreate()
df = spark.createDataFrame([("Java", "20000"), ("Python", "100000"), ("Scala", "3000")])
df.printSchema()

＃输出：-

root
 |-- _1: string (nullable = true)
 |-- _2: string (nullable = true)

但是当我这样做时，df.show()它显示错误为：

Py4JJavaError                             Traceback (most recent call last)
C:\Users\PRATIK~1\AppData\Local\Temp/ipykernel_20924/3726558592.py in <module>
----> 1 df.show()

C:\Spark\spark-3.2.1-bin-hadoop3.2\python\pyspark\sql\dataframe.py in show(self, n, truncate, vertical)
    492 
    493         if isinstance(truncate, bool) and truncate:
--> 494             print(self._jdf.showString(n, 20, vertical))
    495         else:
    496             try:

C:\Spark\spark-3.2.1-bin-hadoop3.2\python\lib\py4j-0.10.9.3-src.zip\py4j\java_gateway.py in __call__(self, *args) …