小编mup*_*909的帖子

我正在 Rust 中测试自定义双向迭代器，但遇到了错误

error[E0382]: borrow of moved value: `iter`
   --> src/main.rs:40:13
    |
37  |     let mut iter = BiIterator::from(vec![1, 2, 3]);
    |         -------- move occurs because `iter` has type `BiIterator<i32>`, which does not implement the `Copy` trait
38  |     for i in iter {
    |              ----
    |              |
    |              `iter` moved due to this implicit call to `.into_iter()`
    |              help: consider borrowing to avoid moving into the for loop: `&iter`
39  |         if i == 3 {
40  |             iter.position(0); …

有没有办法从用户提供的 Rust 中的 &str 类型获取函数指针。示例： use 提供了用户提供的函数名称我需要某种方式来调用该函数，最好是闭包或函数指针