我编写了以下程序和程序抛出编译错误
我不知道为什么会出现错误,因为所有的分号和括号似乎都已到位
import java.io.*;
public class Solution {
public static void main(String args[]) throws Exception {
long coords[5000][2];
long number;
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
try {
number = Long.parseLong(br.readline()); // take no of inputs
//take all co ordinates and store it in 2d array
for(long i=0;i<number;i++) {
coords[i][0] = Long.parseLong(br.readline());
coords[i][1] = Long.parseLong(br.readline());
}
} catch(NumberFormatException e) {
System.out.println("Number Format Exception:");
}
if(check_line(coords,number)) {
System.out.println("YES");
} else {
System.out.println("NO");
}
}
public boolean check_line(long coords[][], long limit) { …我正在尝试使用php代码片段进行jQuery Cycle Slideshow,但是控制台给了我这个错误:
"未捕获的SyntaxError:意外的令牌<"
var startingSlide = <?php echo $_GET["thumb"] ?>;
$(slideshowContainer).cycle ({
startingSlide: startingSlide
});
如何正确使用PHP代码？
我很感激你的帮助.
在下面的代码中,最后一行是什么(括号内的位)？
谢谢!!
(function (window, $, my, undefined) {
'use strict';
if (!$) { throw 'jQuery not found.'; }
my.someNamespace = {
bla:null,
blabla:null,
init: function(){},
bind: function(){}
};
} (window, $, window.my = window.my || {}));
我有以下代码
class battleShips {
constructor(squareNr) {
this.squareNr = squareNr;
this.createField();
}
createField() {
let shipsCount = 0;
for (let i = 0; i < this.squareNr; i++) {
let fieldSquare = document.createElement("div");
fieldSquare.className = "squareStyle";
document.querySelector(".arrayWrap").appendChild(fieldSquare);
fieldSquare.setAttribute("value", "false");
this.selectShips(fieldSquare, shipsCount);
}
}
selectShips(square, count) {
square.addEventListener("click", function() {
if (square.getAttribute("value") === "false") {
square.setAttribute("value", "true");
square.style.backgroundColor = "green";
count += 1;
console.log(count);
document.querySelector(".shipCounter").textContent = "You have selected " + count + " ships";
} else {
square.setAttribute("value", "false");
square.style.backgroundColor = "white"; …var input = [
["0001", "Roman", "USA", "21/05/1989", "read"],
["0002", "jack", "UK", "10/10/1992", "singing"],
["0003", "harry", "Poland", "25/12/1965", "cook"],
["0004", "Malay", "Martapura", "6/4/1970", "Sport"]
]
function Handling() {
// ...
}
有人可以帮我解决这个数组问题吗？
结果应该是这样的：
Run Code Online (Sandbox Code Playgroud)ID: 0001 Name: Roman Born Place: USA 21/05/1989 Hobby: read
因此,我正在尝试构建用户被提示输入"摇滚","纸张"或"剪刀"的代码,然后将其与随机计算机选择进行比较.计算机的选择被认为是0到1之间的随机值.我们的比较函数通过这两个选项并比较它们的值以返回输出,告诉哪个手势信号获胜.我收到语法错误,但似乎无法弄清楚我错过了什么.
var userChoice = prompt("Do you choose rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
computerChoice = "rock";
} else if (computerChoice <= 0.67) {
computerChoice = "paper";
} else {
computerChoice = "scissors";
}
var compare = function(choice1, choice2) {
if (choice1 === choice2) {
return "The result is a tie!";
} else if (choice1 === "rock") {
if (choice2 === "scissors") {
return "rock wins";
} else {
return "paper wins";
}
} …我用以下方式在JavaScript中编写php.即使删除功能工作,警报也没有到来.
这是我的代码:
<script type="text/javascript">
function delete_id(id) {
if (confirm('Are you sure To Remove This Record ?')) {
<?php
include('database_connect.php');
if (isset($_GET['variable'])) {
$sql_query = "DELETE FROM register WHERE id=".$_GET['variable'];
mysqli_query($con, $sql_query);
header("Location: newusers.php");
}
mysqli_close($con);
?>
}
}
</script>
我有来自服务器的 JSON 响应，在此数据中，我在文本中有一个“返回行”。
{text: "I am in the first line ? and I am in the second line"}
但是当我在 html 中显示它时，没有显示“返回行”。
"I am in the first line and I am in the second line"
代替：
I am in the first line
and I am in the second line
任何使用 HTML 或 CSS（可能是 JavaScript）的解决方案？
谢谢 ！