我正在iOS上使用UncaughtExceptionHandler:
NSSetUncaughtExceptionHandler(&myHandler);
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void myHandler(NSException * exception)
{
//i can get stack symbols from
//exception.callStackSymbols;
}
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6 UIKit 0x000000018a6622c8 <redacted> + 612
7 UIKit 0x000000018a678b88 <redacted> + 592
8 UIKit 0x000000018a678814 <redacted> + 700
9 UIKit 0x000000018a671d50 <redacted> + 684
10 UIKit 0x000000018a644f74 <redacted> + 264
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/Users/my_user/Library/Developer/Xcode/iOS\ DeviceSupport/8.4.1\ \(12H321\)/symbols/system/Library/Frameworks/UIKit.framework/UIKit
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6 UIKit 0x000000018a6622c8 <redacted> + 612
xcrun atos -arch arm64 -o /Users/my_user/Library/Developer/Xcode/iOS\ DeviceSupport/8.4.1\ \(12H321\)/symbols/system/Library/Frameworks/UIKit.framework/UIKit -l 0x18a662064 0x000000018a6622c8
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我无法从此命令中找到正确的输出.
如何象征UIKit等系统框架?
我向WindowManager添加了一个浮动视图,并使其可以在屏幕上移动,我可以在单击此视图时执行单击事件,一切正常.
但是,我不知道如何在espresso或UIAutomator中访问此视图.
final WindowManager.LayoutParams layoutParams = new WindowManager.LayoutParams(
WindowManager.LayoutParams.MATCH_PARENT,
WindowManager.LayoutParams.MATCH_PARENT,
type,
WindowManager.LayoutParams.FLAG_NOT_FOCUSABLE
| WindowManager.LayoutParams.FLAG_WATCH_OUTSIDE_TOUCH
| WindowManager.LayoutParams.FLAG_LAYOUT_NO_LIMITS,
PixelFormat.TRANSLUCENT
);
ImageView floatingView = new ImageView(mContext);
floatingView.setContentDescription("bugtags_fab_des_normal");
mWindowManager.addView(floatingView, layoutParams);
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rect中的白蓝色图标是我正在谈论的浮动视图.
浮动视图响应单击事件,并执行一些任务,现在我想在AndroidJunit测试中执行此操作.
我使用onView方法尝试Espresso,但测试用例:
onView(withContentDescription("bugtags_fab_des_normal")).perform(click());
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得到:
android.support.test.espresso.NoMatchingViewException: No views in hierarchy found matching: with content description: is "bugtags_fab_des_normal"
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我尝试UIAutomator Viewer,但我在视图层次结构中找不到floatingView.
如何在espresso或uiautomator中访问此视图并执行单击操作?
@Test
public void testInvoke() {
onView(withContentDescription("bugtags_fab_des_normal")).perform(click());
}
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实际上,我使用的是一个名为bugtags.com的sdk ,它是一个简单的app bug报告和崩溃分析工具.
android android-testing android-espresso android-uiautomator
我正在使用Android Studio 1.4预览版3,gradle插件1.3。嗨,我将aar包上传到bintray jcenter:
https://bintray.com/kevinho/maven/opencore-amr-android/view
我设置了这样的存储库:
buildscript {
repositories {
jcenter()
}
dependencies {
classpath 'com.android.tools.build:gradle:1.3.0'
classpath 'com.jfrog.bintray.gradle:gradle-bintray-plugin:1.2'
classpath 'com.github.dcendents:android-maven-gradle-plugin:1.3'
}
}
allprojects {
repositories {
jcenter()
}
}
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当我尝试将其用作依赖项时,
dependencies {
compile fileTree(dir: 'libs', include: ['*.jar'])
compile 'com.hikvh:opencore-amr-android:1.0.0'
}
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我收到以下错误:
错误:配置项目':app'时发生问题。找不到opencore-amr-android.jar(com.hikvh:opencore-amr-android:1.0.0)。在以下位置搜索:https : //jcenter.bintray.com/com/hikvh/opencore-amr-android/1.0.0/opencore-amr-android-1.0.0.jar
我的问题是:为什么gradle默认会尝试加载jar而不是aar文件?以及如何解决这个问题?
我想在一些耗时的方法上做一些工具,比如 org/json/JSONObject.toString()使用ASM Java框架.
public class JSONUsage {
public void callToString() {
JSONObject jsonObject = new JSONObject();
String a = jsonObject.toString();//original call
System.out.println(a);
}
}
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public class JSONUsage {
public void callToString() {
JSONObject jsonObject = new JSONObject();
// **important!**
//pass the instance as an param, replace the call to a static method
String a = JSONReplacement.jsonToString(jsonObject);
System.out.println(a);
}
}
public class JSONReplacement {
public static String jsonToString(JSONObject jsonObject) {
//do the time caculation
long before …Run Code Online (Sandbox Code Playgroud) 我正在开发一个spring boot应用程序:
使用依赖项:
dependencies {
compile("org.springframework.boot:spring-boot-starter-web:1.4.1.RELEASE")
compile('org.springframework.boot:spring-boot-starter-data-jpa:1.4.1.RELEASE')
compile('mysql:mysql-connector-java:5.1.39')
}
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我想在init上运行sql:
SET NAMES 'utf8mb4'
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支持表情符号读/写
我在application.properties上进行了这些配置
spring.datasource.tomcat.init-sql=SET NAMES 'utf8mb4'
spring.datasource.init-sql=SET NAMES 'utf8mb4'
spring.datasource.connection-init-sql=SET NAMES 'utf8mb4'
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但我无法使它工作,并且在应用程序启动时没有这个日志.