小编Or *_*zaz的帖子

我正在使用Google API和MapActivity,MapView等.
当我需要获取当前位置时,我会在第一时间使用此代码:

myLocationManager =(LocationManager)getSystemService(Context.LOCATION_SERVICE);
// Sets the criteria for a fine and low power provider
Criteria crit = new Criteria();
crit.setAccuracy(Criteria.ACCURACY_FINE);
crit.setPowerRequirement(Criteria.POWER_LOW);    
// Gets the best matched provider, and only if it's on
String provider = myLocationManager.getBestProvider(crit, true);
// If there are no location providers available
if (provider == null){
    OnClickListener listener = new OnClickListener() {

        public void onClick(DialogInterface dialog, int which) {
            // Closes the activity
            finish();
        }
    };
    Utils.getInstance().showAlertDialog(this, R.string.warning_dialog_title,
                               R.string.no_location_providers_error_message,
                            android.R.drawable.ic_dialog_alert, false, listener);
}
// Location …

我正在尝试创建一个DialogFragment,其中嵌入了一个ListFragment.我正在使用4.2.2中添加的嵌套片段我将它与支持库一起使用,因此我的api版本应该无关紧要(对于记录,我的操作系统版本也是4.2.2).

我正在尝试添加的listfragment现在只显示字符串,因为我正在尝试添加它,在我这样做之后,列表将有图像等等.所以请将任何将字符串列表传递给对话框的想法对我不好,我的列表会更复杂..此外,我正在尝试将此片段重用于平板电脑模式.列表始终应该以该模式显示.因此重用很重要.

我的问题是当我尝试将listfragment添加到对话框的FrameLayout时,无法找到它:

java.lang.IllegalStateException:Fragment在android.support.v4.app.Fragment $ 1.findViewById(Fragment.java:1425)的android.support.v4.app.FragmentManagerImpl.moveToState(FragmentManager.java:901)中没有视图)位于android.support.v4.支持的android.support.v4.app.FragmentManagerImpl.moveToState(FragmentManager.java:1088),android.support.v4.Ad.FragmentManagerImpl的android.support.v4.app.BackStackRecord.run(BackStackRecord.java:682). execPendingActions(FragmentManager.java:1444)在android.support.v4.app.Fragment.performStart(Fragment.java:1481)的android.support.v4.app.FragmentManagerImpl.moveToState(FragmentManager.java:941)android.support .v4.app.FragmentManagerImpl.moveToState(FragmentManager.java:1088)位于android.support.v4.app.BackStackRecord.run(BackStackRecord.java:682)android.support.v4.app.FragmentManagerImpl.execPendingActions(FragmentManager.java) :1444)在android.os.Handler.handleCallback(Handler.java:725)的android.support.v4.app.FragmentManagerImpl $ 1.run(FragmentManager.java:429)在android.os.Handler.dispatchMessage(Handler.java:92)的android.app.Looper.loop(Looper.java:137)在android.app.ActivityThread.main(ActivityThread.java:5041)的java.lang上.在com.android.internal.os.ZygoteInit $ MethodAndArgsCaller.run(ZygoteInit.java:793)的com.android.internal.os.ZygoteInit上的java.lang.reflect.Method.invoke(Method.java:511)中的reflect.Method.invokeNative(Native Method). android.internal.os.ZygoteInit.main(ZygoteInit.java:560)at dalvik.system.NativeStart.main(Native Method)

添加:

也许这个新信息很重要,DialogFragment显示在SupportMapFragment中.当我尝试在SupportMapFragment中显示ListFragment时,它可以工作.此外,当我试图在SupportMapFragment中显示DialogFragment时 - 它可以工作.

就在我尝试在DialogFragment中显示ListFragment时,它失败了.所以它看起来像这样:FragmentActivity - > SupportMapFragment - > DialogFragment - > ListFragment.

SupportMapFragment中显示的DialogFragment如下所示:

// DialogFragment.show() will take care of adding the fragment
// in a transaction.  We also want to remove any currently showing
// dialog, so make our own transaction and take care of that here.
FragmentTransaction ft = getChildFragmentManager().beginTransaction();
SherlockDialogFragment prev =(SherlockDialogFragment)getChildFragmentManager().findFragmentByTag("dialog");
if (prev != null) {
    ft.remove(prev);
} …