我需要使用map函数ex创建一个视图:
function(doc, meta) {
if(doc.docType == "testDoc")
emit(meta.id, doc)
}
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我必须使用沙发床Java客户端2.1创建此视图。文档中找不到任何东西,谢谢
我正在尝试将Flot图表集成到 React 中,但我得到$.plot的不是函数错误,我有以下代码
脚本标签 Index.html
<script src="dist/libs/js/jquery.min.js"></script>
<script src="dist/libs/js/jquery.flot.js"></script>
<script src="dist/libs/js/jquery.flot.stack.js"></script>
<script src="dist/libs/js/jquery.flot.symbol.js"></script>
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我的反应组件
class OfferGraph extends React.Component {
constructor(){
super();
this.state ={
isLogged:false
}
//Test Code
let node = $('#trackInsightGraph');
$.plot(node, [{
data: data['searchAverage'],
points: {show: false}
}, {
data: data['offer'],
points: {show: false}
}, {
data: data['similar'],
points: {show: false}
}, {
data: data['c01'],
lines: {show: true}
}], options);
}
render(){
return <div id="trackInsightGraph">
</div>
}
}
export default OfferGraph;
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我不能使用另一个 Chart 库,因为大多数功能是为Flot …
我试图在java中实现ftp下载.我正在使用apache common-net library但是我得到了这个异常.我打印出下面的堆栈跟踪我不知道我错过了什么
org.apache.commons.net.ftp.FTPConnectionClosedException: Connection closed without indication.
at org.apache.commons.net.ftp.FTP.__getReply(FTP.java:317)
at org.apache.commons.net.ftp.FTP.__getReply(FTP.java:294)
at org.apache.commons.net.ftp.FTP.sendCommand(FTP.java:483)
at org.apache.commons.net.ftp.FTP.sendCommand(FTP.java:608)
at org.apache.commons.net.ftp.FTP.sendCommand(FTP.java:582)
at org.apache.commons.net.ftp.FTP.pasv(FTP.java:1007)
at org.apache.commons.net.ftp.FTPClient._openDataConnection_(FTPClient.java:869)
at org.apache.commons.net.ftp.FTPClient._retrieveFile(FTPClient.java:1854)
at org.apache.commons.net.ftp.FTPClient.retrieveFile(FTPClient.java:1845)
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我有一个方法如下
public void downloadFromFtp(Map<String, String> ftpMap, String sourceWithPath,
String destinationFolder) throws IOException {
String hostname = ftpMap.get("hostname");
String username = ftpMap.get("username");
String password = ftpMap.get("password");
if (null == hostname || null == username || null == password) {
throw new InvalidInputException(
"Invalid RMS FTP hostname/username/password");
}
//Connect to ftp url
ftpClient.connect(hostname, 21);
ftpClient.setFileType(FTP.BINARY_FILE_TYPE);
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