我看到了几个我正在考虑的例子,但它们并不是我正在寻找的......道歉,如果这是一个重复的帖子:
所以,我有这个函数读取数组中的项目,我定期添加(目前,我在列表中有超过50个项目).它将所有内容放在一个列表中(<ul>).
function getListItems()
{
$listItems = array(
1 => "List Item 1",
2 => "List Item 2",
3 => "List Item 3",
4 => "List Item 4",
5 => "List Item 5",
6 => "List Item 6",
7 => "List Item 7",
8 => "List Item 8",
9 => "List Item 9",
10 => "List Item 10",
11 => "List Item 11",
12 => "List Item 12",
13 => "List Item 13",
14 => "List Item 14",
15 => …Run Code Online (Sandbox Code Playgroud) 如何在SELECT中找到一年中的第一天?
SELECT `DATE`,`SomeValue1`,`SomeValue2`
FROM `SomeTableName`
WHERE (`DATE` >= [...first day of the year in date format...])
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我发现这个月 - 但我没有足够的掌握一年:(我一直在寻找这个单独的查询来查找月初和现在之间的数据)
WHERE (`DATE` between DATE_FORMAT(NOW() ,'%Y-%m-01') AND NOW() )
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