小编use*_*442的帖子

我试用了Zend Framework 2框架应用程序,它在Zend Server 5.6(PHP版本5.4.0 apache 2.2.21 MYSQL 5.0.10)中运行良好.但我希望Zend Framework 2与MS SQL 2008连接.我尝试了以下但它不起作用并抛出异常"将无效参数传递给sqlsrv_execute".

'db' => array(
    'driver'    => 'sqlsrv',
    'hostname'  => 'testserver\test',
    'Database'  => 'payroll',
    'UID'       => 'sa',
    'PWD'       => '123456'
),

以上db数组有什么问题？请用正确的连接字符串建议我

仅供参考:

我测试了PHP 5.4和MS SQL 2008连接,它工作正常,以下连接成功建立.

/*
$serverName = "testserver\test"; //serverName\instanceName
$connectionInfo = array( "Database"=>"payroll", "UID"=>"sa", "PWD"=>"123456");
$conn = sqlsrv_connect( $serverName, $connectionInfo);
if( $conn ) {
    echo "---------- Connection established --------------------.<br />";     
    $sql = "select * from users";
    $stmt = sqlsrv_query($conn, $sql);
    while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) …