小编mat*_*zin的帖子

如何将应用程序中的活动上下文传递给其他应用程序中的服务

所以我在启动服务的应用程序中有一个活动:

private void startService() {
    if (started) {
        Toast.makeText(Main.this, "Service already started",
                Toast.LENGTH_SHORT).show();
    } else {
        Intent i = new Intent();
        i.setClassName("com.enorbitas.daemon.service",
                "com.enorbitas.daemon.service.DaemonService");
        startService(i);
        started = true;
        updateServiceStatus();
        Log.d(getClass().getSimpleName(), "startService()");
    }

}
Run Code Online (Sandbox Code Playgroud)

该活动由以下意图启动:

<intent-filter>
            <action android:name="android.hardware.usb.action.USB_DEVICE_ATTACHED" />
        </intent-filter>
Run Code Online (Sandbox Code Playgroud)

然后,该服务执行日志记录并与此自定义USB设备连接.为此,它需要活动上下文:

        mUsbManager = (UsbManager) parent.getSystemService(Context.USB_SERVICE);
        HashMap<String, UsbDevice> deviceList = mUsbManager.getDeviceList();
        Iterator<UsbDevice> deviceIterator = deviceList.values().iterator();
        while(deviceIterator.hasNext()){
            UsbDevice device = deviceIterator.next();
        }

        Intent intent = parent.getIntent();
        String action = intent.getAction();
        UsbDevice device = (UsbDevice) intent
                .getParcelableExtra(UsbManager.EXTRA_DEVICE);
        if (UsbManager.ACTION_USB_DEVICE_ATTACHED.equals(action)) {
            setDevice(device);
            Log.i(TAG, "usb conectado");
        } …
Run Code Online (Sandbox Code Playgroud)

service android android-context

6
推荐指数
1
解决办法
1万
查看次数

标签 统计

android ×1

android-context ×1

service ×1