我有一个非常奇怪的问题,我实施了:
- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo fetchCompletionHandler:(void (^)(UIBackgroundFetchResult result))completionHandler
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用于静音远程推送通知.当应用程序处于后台并连接到Xcode时,它非常适用.当我拔下任何iOS设备并运行应用程序时,请移至后台并发送远程通知,didReceiveRemoteNotification:fetchCompletionHandler而不是被调用.
我的代码如下:
- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo fetchCompletionHandler:(void (^)(UIBackgroundFetchResult))completionHandler {
NSInteger pushCode = [userInfo[@"pushCode"] integerValue];
NSLog(@"Silent Push Code Notification: %i", pushCode);
NSDictionary *aps = userInfo[@"aps"];
NSString *alertMessage = aps[@"alert"];
if (pushCode == kPushCodeShowText) {
UILocalNotification *localNotif = [[UILocalNotification alloc] init];
localNotif.fireDate = [NSDate date];
localNotif.timeZone = [NSTimeZone defaultTimeZone];
localNotif.alertBody = alertMessage;
localNotif.alertAction = @"OK";
localNotif.soundName = @"sonar.aiff";
// localNotif.applicationIconBadgeNumber = 0;
localNotif.userInfo = nil;
[[UIApplication sharedApplication] presentLocalNotificationNow:localNotif];
UILocalNotification *clearNotification …Run Code Online (Sandbox Code Playgroud) debugging background objective-c apple-push-notifications ios
到目前为止,我看到了获取多个电话号码的方法,如果我显示一个选择器,那么用户可以选择人员,然后获取电话号码.我想要的是检索所有联系人的号码. 它甚至可能吗?
我正在尝试测试区域监控,因为我正在获得这样的当前位置:
- (void)startLocationTracking
{
CLLocationManager *locationManager = [[CLLocationManager alloc] init];
// Start location manager
if ([CLLocationManager locationServicesEnabled] && [CLLocationManager authorizationStatus] == kCLAuthorizationStatusAuthorized) {
locationManager = [LocationTracker sharedLocationManager];
locationManager.delegate = self;
[locationManager startMonitoringSignificantLocationChanges];
}
}
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并跟踪区域监控的第一个位置,如下所示:
-(void)locationManager:(CLLocationManager *)manager didUpdateLocations:(NSArray *)locations
{
static dispatch_once_t onceToken;
dispatch_once(&onceToken, ^{
CLRegion *region = [[CLRegion alloc] initCircularRegionWithCenter:manager.location.coordinate radius:300 identifier:@"first location initializer"];
NSLog(@"0: %@", manager.location);
NSLog(@"1: %@", region);
[manager startMonitoringForRegion:region];
NSLog(@"[locationManager startMonitoringForRegion:%@];", region);
});
}
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然后在当前区域的每个出口处,我正在监视新位置,如下所示:
- (void)locationManager:(CLLocationManager *)manager didEnterRegion:(CLRegion *)region
{
NSLog(@"%s, %@", __PRETTY_FUNCTION__, region);
} …Run Code Online (Sandbox Code Playgroud) 我看到了一些关于在同一个类中添加观察者和句柄的例子,但我想知道的是,是否可以在第一个视图控制器中添加观察者并在第二个视图控制器中处理它?
我希望不断从第一个视图控制器发送距离并在第二个控制器中处理它.第二个视图控制器添加为子视图:addSubview,addChildViewController.
它就像android中的广播一样.
objective-c observers nsnotification nsnotificationcenter ios
点击"myLocation"按钮时,我想做一些事情.到目前为止,我UIButton自己:
UIButton *btnMyLoc = (UIButton*)[self.googleMapView subviews].lastObject;
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但这还不够.有任何想法吗?
根据我的理解,这是一个内存问题,特别是因为我用不同的定时器从几个地方多次调用该方法.
抛出异常的代码如下:
- (NSMutableArray*)getAllTraps
{
@synchronized(self)
{
self.fetchRequest = [[NSFetchRequest alloc] initWithEntityName:@"Trap"];
NSError *error = nil;
NSArray *results = [self.managedObjectContext executeFetchRequest:self.fetchRequest error:&error];
if (!results)
{
NSLog(@"Error fetching traps: %@", error.localizedDescription);
NSLog(@"Reason: %@", error.localizedFailureReason);
NSLog(@"Suggestion: %@", error.localizedRecoverySuggestion);
abort();
}
if (error != nil)
{
// Handle error
NSLog(@"Error getting all traps");
}
else
{
// Handle success
NSLog(@"Success getting all traps");
}
NSMutableArray *arrayOfAllTraps = [[NSMutableArray alloc] init];
for (int i = 0; i < results.count; i++)
{
Trap *singleTrap = …Run Code Online (Sandbox Code Playgroud) 我有一个UITableView自定义UILabel标题和另一个副标题,以便将文本对齐.
我的数据来自Web服务,这是我在分析和存储NSArray的NSDictionary.一些标题或副标题可以是零/空文本.为此,我把它放在try/catch中.
我的桌子中的一条线让我的应用程序粉碎,我无法弄清楚原因.
我认为其中一个(标题/副标题)返回,NSDictionary 但我为我的对象做了一个日志打印,对于我来说[UILabel text],似乎一切都好.
异常和堆栈跟踪:
2014-04-29 10:47:55.985 Cellular Radar[3226:60b] -[__NSDictionaryI length]: unrecognized selector sent to instance 0x16d007f0
2014-04-29 10:47:55.993 Cellular Radar[3226:60b] -[Home tableView:willDisplayCell:forRowAtIndexPath:], exception.reason: -[__NSDictionaryI length]: unrecognized selector sent to instance 0x16d007f0
2014-04-29 10:47:55.999 Cellular Radar[3226:60b] -[__NSDictionaryI length]: unrecognized selector sent to instance 0x16d007f0
2014-04-29 10:47:56.006 Cellular Radar[3226:60b] CRASH:
-[__NSDictionaryI length]: unrecognized selector sent to instance 0x16d007f0
2014-04-29 10:47:56.062 Cellular Radar[3226:60b] Stack Trace:
(
0 CoreFoundation 0x30e02feb …Run Code Online (Sandbox Code Playgroud) 我在后台线程中将NSOperation子类化为http post.那些特定的http帖子不需要返回任何值.
我想要做的是当我出现错误或超时时我希望它在增加延迟后发送(斐波那契).
到目前为止我已经这样做了:
NSInternetOperation.h:
#import <Foundation/Foundation.h>
@interface NSInternetOperation : NSOperation
@property (nonatomic) BOOL executing;
@property (nonatomic) BOOL finished;
@property (nonatomic) BOOL completed;
@property (nonatomic) BOOL cancelled;
- (id)initWebServiceName:(NSString*)webServiceName andPerameters:(NSString*)parameters;
- (void)start;
@end
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NSInternetOperation.m:
#import "NSInternetOperation.h"
static NSString * const kFinishedKey = @"isFinished";
static NSString * const kExecutingKey = @"isExecuting";
@interface NSInternetOperation ()
@property (strong, nonatomic) NSString *serviceName;
@property (strong, nonatomic) NSString *params;
- (void)completeOperation;
@end
@implementation NSInternetOperation
- (id)initWebServiceName:(NSString*)webServiceName andPerameters:(NSString*)parameters
{
self = [super init];
if (self) {
_serviceName …Run Code Online (Sandbox Code Playgroud) 我正在尝试考虑一种方法来使用UIActivityViewController(或使用SMS)从一个设备与另一个设备共享联系.
到目前为止,我一直在寻找,我不知道如何使用我的应用程序在设备之间共享联系人.
有任何想法吗?
我使用内置的MZFayeClient(https://github.com/m1entus/MZFayeClient)WebSocket.我需要实现长轮询技术.怎么做?从哪儿开始?没有关于如何操作的信息(或足够的信息),或者是否存在具有长轮询的Faye库.
ios ×10
objective-c ×7
background ×1
clregion ×1
contacts ×1
core-data ×1
debugging ×1
faye ×1
long-polling ×1
nsoperation ×1
observers ×1
uitableview ×1