小编Jai*_*ind的帖子

我想在两个表中插入数据,这两个表都属于不同的服务器.我已经知道链接服务器做同样的工作.但我正在寻找其他方法来解决这个问题.

我有两张桌子说TABLE_1和TABLE_2

TABLE_1属于服务器1,TABLE_2属于服务器2.

我想在不使用链接服务器的情况下一次在两个表中插入数据.还有其他出路吗？

提前致谢

我已经花了很多时间来解决问题.我正在调用第三方API

HTTP://abc/app.aspx deFleetLastName = MYNAME与Test123&deFleetFirstName =ààÃÅjeetaSisodiààÃÅ

在上面的网址中,我想允许在诸如MyName和Test123之类的单词之间.另外我想允许像ààÃÅjeetaSisodiààÃÅ这样的西班牙语字符

我使用下面的代码来允许西班牙语字符和它的工作正常.

AuthRequest = "&deTCIVRAccountNumber=" + SecCardReq.AdminNumber;
                AuthRequest += "&deCISSTitle=" + SecCardReq.Title;
                AuthRequest += "&deTCIVRCardHolderIdentFirstName=" + SecCardReq.FirstName;
                AuthRequest += "&deTCIVRCardHolderIdentMiddleName=" + SecCardReq.MiddleName;
                AuthRequest += "&deTCIVRCardHolderIdentLastName=" + SecCardReq.LastName;
                AuthRequest += "&deCISSSecLastName=" + SecCardReq.SecLastName;
                AuthRequest += "&deCISSNameOnCard=" + SecCardReq.NameOnCard;
                AuthRequest += "&deTCIVRCardHolderIdentAddressLine1=" + SecCardReq.AddressLine1;
                AuthRequest += "&deTCIVRCardHolderIdentAddressLine2=" + SecCardReq.AddressLine2;
                AuthRequest += "&deTCIVRCardRegistrationCity=" + SecCardReq.City;
                AuthRequest += "&deTCIVRCardHolderIdentificationStateProvince=" + SecCardReq.State;
                AuthRequest += "&deTCIVRCardRegistrationPostalCode=" + SecCardReq.PostalCode;
                AuthRequest += "&deTCIVRCardRegistrationCountry=" + SecCardReq.Country;
                AuthRequest += "&deTCIVRCardRegistrationEmail=" + SecCardReq.Email;
                AuthRequest += …

我有以下SQL语句.它抛出以下错误:"只有一个结果允许SELECT作为表达式的一部分".我的sql语句的目标是获取制造"最便宜"贿赂的员工的姓名.

括号之间的部分返回employee_id和每天花费的金额(相对最便宜的贿赂).这是两个结果,而我只想要employee_id.所以我只想使用MIN部分来获得正确的employee_id.我怎样才能做到这一点？

SELECT Voornaam, Achternaam
FROM Medewerker m JOIN
     (
      SELECT Medewerker_id
      FROM Steekpenning
      ORDER BY -1*Bedrag/(julianday(Begindatum) - julianday(Einddatum))
      limit 1
     ) s
     on m.Medewerker_id = s.Medewerker_id;

编辑答案.如何扩展此查询以仅显示本月开始的贿赂？我想我需要使用这样的东西？(julianday(Begindatum) - julianday('现在'))> 31但在哪里？

问候.CAS