小编ord*_*rde的帖子

尝试使用 ruby​​ 迭代数组，结果惨败，

My Array
people = [{first_name: "Gary", job_title: "car enthusiast", salary: "14000" },
{first_name: "Claire", job_title: "developer", salary: "15000"},
{first_name: "Clem", job_title: "developer", salary: "12000"}]

如何迭代上面的哈希以仅输出工资值？？？

我尝试使用：

people.each do |i,j,k|
  puts "#{i}"
end

结果如下，不是我想要的，

{:first_name=>"Gary", :job_title=>"car enthusiast", :salary=>"14000"}
{:first_name=>"Claire", :job_title=>"developer", :salary=>"15000"}
{:first_name=>"Clem", :job_title=>"developer", :salary=>"12000"}

有没有办法迭代这个数组并仅列出工资值而不列出其余值？

这是我第一次涉足计算机编程.我选择学习Ruby,我很享受它.但是,我有点困惑的是为什么答案在这段代码中输出不正确.

def addition_function
    puts "Which numbers would you like to add?"
    @n1 = gets.chomp
    @n2 = gets.chomp
    @n1 + @n2 == @answer
    puts "The sum is... #{@answer}"
end

def subtraction_function
    puts "Which numbers would you like to subtract?"
    @n1 = gets.chomp.to_i
    @n2 = gets.chomp.to_i
    @n1 - @n2 == @answer
    puts "The answer is... #{@answer}"
end

def multiplication_function
puts "Which numbers would you like to multiply?"
    @n1 = gets.chomp
    @n2 = gets.chomp
    @n1 * @n2 == @answer
    puts "The answer is... …

在http://learnrubythehardway.org/book/ex35.html的第7行,有一条评论说明有一个错误.

当这个程序运行并且您选择一个包含的数字时,既不是"0"也不是"1",它会说它不是数字.如何让它检测所有数字？

这是代码:

def gold_room
  puts "This room is full of gold.  How much do you take?"

  print "> "
  choice = $stdin.gets.chomp

  # this line has a bug, so fix it
  if choice.include?("0") || choice.include?("1")
    how_much = choice.to_i
  else
    dead("Man, learn to type a number.")
  end

  if how_much < 50
    puts "Nice, you're not greedy, you win!"
    exit(0)
  else
    dead("You greedy bastard!")
  end
end

我有一个字符串:"C:/This/is/a/windows/path/file20110312name20120221.csv".

我想提取所有日期(例如[0-9]{8}).

通常,如何从较大的字符串中提取与模式匹配的子字符串？