小编r2g*_*get的帖子

嗨,我正在使用fineupload多文件上传脚本,但有一些我无法掌握.我正在尝试制作一个php服务器端文件处理脚本.

当你包括

<script type="text/javascript">
$(document).ready(function() {
    var uploader = new qq.FileUploader({
        element: $('#manualUploadModeExample')[0],
        action: "core/up.php",
        autoUpload: false,
        demoMode: false,
        debug: false,
        multiple: true,
        maxConnections: 3,
        disableCancelForFormUploads: false,
        //0 is geen limit getal in bytes
        minSizeLimit: 0,
        sizeLimit: 0,
        inputName: "qqfile",
        uploadButtonText: "Select Files",
        cancelButtonText: "verwijder",
        failUploadText: "Upload mislukt"
    });

    $('#triggerUpload').click(function() {
        uploader.uploadStoredFiles();
    });
});

显示它的HTML

    <div id="Upload">
    <noscript>
        <p>Please enable JavaScript to use file uploader.</p>
        <!-- or put a simple form for upload here -->
    </noscript>
    <ul id="manualUploadModeExample" …

我希望用户提交youtube网址.如果youtube链接正确,我想"动态"检查,如果检查成功,则将输入旁边的文本更改为OK.

我设法做了验证功能,但它不起作用.我究竟做错了什么？

UPDATE

它仍然无法正常工作,当URL不正确时应该说不正确,而在输入时URL正确时可以正常:

            $('form #youtube').bind("change keyup input", validYT());
        function validYT()
        {

            var url = $('form #youtube').val();
            var p = /^(?:https?:\/\/)?(?:www\.)?youtube\.com\/watch\?(?=.*v=((\w|-){11}))(?:\S+)?$/;
            if (url.match(p)) {
                $('#ytInfo').removeClass().addClass('fieldok ').text('OK');
                return true
            }
            else
            {
                $('#ytInfo').removeClass().addClass('fieldok ').text('NOT OK');
                return false
            }
        }

HTML:

youtubelink<BR>
<input type="text" name="youtube" id ="youtube" value="" /><div id="ytlInfo">dd</div>