我试图用整数填充我的数组.但是,对我来说有些奇怪的事情并不像我想的那么容易.以下是对所发生情况的描述.
代码的最后一行给了我错误."不允许将int隐式转换为NSArray"
//.h file
{
NSArray storeDisk[15];
}
property int virdCount;
property (nonatomic, strong)NSArray *storeDisk;
//.m file
virdCount+=virdCount;
storeDisk[0]=virdCount;
我在我的应用程序的工作做出iphone 5在下面的代码,为iPhone 4 donebutton工程兼容,但是当涉及到的iPhone5是不是可触摸!我不知道为什么？
float screenSizeHeight=[UIScreen mainScreen].bounds.size.height;
if(screenSizeHeight==568)
{
UIImageView *my_image_view = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"Plain_Background2.png"]];
[my_image_view setFrame:CGRectMake(0,20,320,568)];
[self.view addSubview:my_image_view];
[self.view sendSubviewToBack:my_image_view];
imageScrollView = [[UIScrollView alloc] initWithFrame:CGRectMake(0, 20, 320, 460)];
[doneButtonOutlet setFrame:CGRectMake(124,470,72,28)];
}
if(screenSizeHeight==480)
{
UIImageView *my_image_view = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"Plain_Background.png"]];
[my_image_view setFrame:CGRectMake(0,20,320,480)];
[self.view addSubview:my_image_view];
[self.view sendSubviewToBack:my_image_view];
imageScrollView = [[UIScrollView alloc] initWithFrame:CGRectMake(0, 20, 320, 400)];
[doneButtonOutlet setFrame:CGRectMake(124,432,72,28)];
}
如果某个元素专注于画外音，我会尝试获取信息。因此，我重写了该accessibilityElementDidBecomeFocused方法，但这从未被调用。我忘记了什么吗？
override func viewDidLoad() {
super.viewDidLoad()
viewArray.append(UIView())
viewArray.append(UIView())
viewArray[0].frame = CGRectMake(20, 210, 100, 100)
viewArray[0].isAccessibilityElement = true
self.view.addSubview(viewArray[0])
viewArray[1].frame = CGRectMake(220, 220, 100, 100)
viewArray[1].isAccessibilityElement = true
self.view.addSubview(viewArray[1])
}
//never called
override func accessibilityElementDidBecomeFocused(){
println("accessibilityElementDidBecomeFocused")
}
默认情况下,图表显示2001 - 2002年的数据; 我想知道当用户将鼠标悬停在图表上时,它将显示2002-2003的数据.一旦mouser不在图表中,它应该回到默认阶段.
//The first data comes from 2001-2002
var seriesData = [{
year: "2000",
sold: 100,
produced: 200
}, {
year: "2001",
sold: 250,
produced: 280
}];
// The second dataset comes from 2002-2003
var seriesData2 = [{
year: "2002",
sold: 140,
produced: 240
}, {
year: "2004",
sold: 350,
produced: 380
}];
function createChart() {
$("#chart").kendoChart({
dataSource: {
data: seriesData
},
series: [{
name: "Sold",
field: "sold"
}, {
name: "Producted",
field: "produced"
}],
categoryAxis: {
field: …必须删除路径的所有单点组件.
例如,"abi /./ bune"应该标准化为"abi/bune".
必须删除路径的所有双点组件及其父目录.例如,"abi/ba /../ bune"应归一化为"abi/bune".
不使用正则表达式.任何想法如何实现？
我有以下javascript对象:
输入
data=[];
data[0]=[{"value":29},{"value":44}]
data[1]=[{"value":16}]
data[2]=[{"value":13},{"value":11},{"value":1}]
data[3]=[{"value":13},{"value":11}]
通过添加来匹配javascript对象长度的所需输出背后的逻辑{value:0}为了实现我已经使用过的所需输出unshift和push操作.这是我想要的输出的说明.
data1 0 0 0
0 data2
0
0 0 0 data3 0 0 0 0 data4
期望的输出
data[0]=[{"value":29},{"value":44},{"value":0},{"value":0},{"value":0},{"value":0},{"value":0},{"value":0}]
data[1]=[{"value":0},{"value":0},{"value":16},{"value":0},{"value":0},{"value":0},{"value":0},{"value":0}]
data[2]=[{"value":0},{"value":0},{"value":0},{"value":13},{"value":11},{"value":1},{"value":0},{"value":0}]
data[3]=[{"value":0},{"value":0},{"value":0},{"value":0},{"value":0},{"value":0}{"value":13},{"value":11}]
电流输出:
如果你看data[2],结果是意外的.我无法处理这个问题.
data[0]=[{"value":29},{"value":44},{"value":0},{"value":0},{"value":0},{"value":0},{"value":0},{"value":0}]
data[1]=[{"value":0},{"value":0},{"value":16},{"value":0},{"value":0},{"value":0},{"value":0},{"value":0}]
data[2]=[{"value":13},{"value":11},{"value":1},{"value":0},{"value":0},{"value":0},{"value":0},{"value":0}]
data[3]=[{"value":0},{"value":0},{"value":0},{"value":0},{"value":0},{"value":0}{"value":13},{"value":11}]
这是FIDDLE
data=[];
data[0]=[{"value":29},{"value":44}]
data[1]=[{"value":16}]
data[2]=[{"value":13},{"value":11},{"value":1}]
data[3]=[{"value":13},{"value":11}]
debugger;
console.log(data);
alllength=0
for (i=0;i<data.length;i++)
{
m= Object.keys(data[i]).length;
alllength=alllength+m;
}
console.log(alllength);
for (i=0;i<data.length;i++)
{
if(i==0)
{
m=Object.keys(data[i]).length;
for(j=0;j<alllength-m;j++)
{
data[i].splice(m+j+1, 0, {"value":0});
}
}
else if(i==data.length-1)
{
n=Object.keys(data[i]).length;
for(j=0;j<alllength-n;j++)
{ …是否可以在应用程序中使用Touch ID传感器,但不能用于登录身份验证？在应用程序中,用户可以扫描另一个人的手指.然后,指纹将与数据库匹配,找到该人的个人资料.
我有以下列表,其中每个列表项具有Start和End值.请注意每个列表项的End值与下一个List项的Start值匹配.
tableItems.Add (new SettingsCellItem() {Start=1000, End=4000});
tableItems.Add (new SettingsCellItem() {Start=4000, End=6000});
tableItems.Add (new SettingsCellItem() {Start=6000, End=8000});
tableItems.Add (new SettingsCellItem() {Start=8000, End=11300});
tableItems.Add (new SettingsCellItem() {Start=11300,End=12000});
允许用户仅更新Start值,当用户输入新Start值时,应在Start再次显示之前根据值对List进行排序.
假设用户将第二个列表项更新{Start=4000,End=6000}为{Start=140,End=6000}
List<SettingsCellItem> sortedList =tableItems.OrderBy(o=>o.Start).ToList();
我得到了以下输出.当您观察到End值不再与Start值匹配时.
电流输出:
{Start=140, End=6000}
{Start=1000, End=4000}
{Start=6000, End=8000}
{Start=8000, End=11300}
{Start=11300,End=12000}
我想知道我怎么能得到以下内容:
期望的输出
{Start=140, End=1000}
{Start=1000, End=6000}
{Start=6000, End=8000}
{Start=8000, End=11300}
{Start=11300,End=12000}
我想在Android和iOS移动应用中使用HighCharts.在Android或iOS中是否可以使用任何库或Gradle依赖项？
我正在使用以下代码从图库中选择图像。当我使用Samsung Galaxy S4对其进行测试时，它会直接转到我真正想要的Gallery。
但是，当我在LG Optimus II设备上测试我的代码时，它显示一个对话框，提供选择图库或图片的选项。换句话说，它增加了我不想要的另一层。
两种设备都具有KitKat 4.4.2操作系统。
public static void showFileChooser(Activity activity) {
Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_PICK);
activity.startActivityForResult(Intent.createChooser(intent, "Select Picture"), 1);
}