小编nid*_*ida的帖子

这是显示PYRAMID但不完全生成所需输出的代码.

function generatePyramid() {
    var totalNumberofRows = 5;
    var arr = new Array();
    for (var i = 1; i <= totalNumberofRows; i++) {
        for (var j = 1; j <= i; j++) {

            arr.push(j);
            console.log(j);
        }
        console.log("\n");
    }
}

我是android的新手.这是我从服务中得到的Json有人请指点我如何在Session(共享首选项)中保存这个JSONResponse我已经在我的SessionManager类中定义了这个函数但是我无法保存它. JSON:

{
    "message": "Successfully Logged In.",
    "auths": "KONG,KONG-Surveyor",
    "user": {
        "view_all_proposals": "0",
        "role_id": "1",
        "contact_no": "020 8547 4333 (x354)",
        "date_modified": "2013-10-10 10:58:56",
        "status": "ACTIVE",
        "profit_margin_limit": "100",
        "cash_code": "KHO",
        "date_created": "2013-02-03 06:41:41",
        "user_initials": "KHO",
        "password": "f10343d1dc8d44c8935b356aa3f8aae2",
        "id": "27",
        "first_name": "Kong",
        "username": "kong",
        "is_admin": "0",
        "address": "Technology Manager",
        "email": "kong.hoang@mrfsgroup.com",
        "proposal_review": "0",
        "last_name": "Hoang",
        "ldap_authentication": "1"
    },
    "status": true,
    "apkStatus": true,
    "apkFileDate": "2013-12-05 04:47:52",
    "apkFile": "2_SurveyAppNew.apk"
}

这是我在SessionManger类中定义的函数:

 public static void setUserObject(Context c, String userObject) {
        SharedPreferences pref = PreferenceManager
                .getDefaultSharedPreferences(c); …

我是android的新手.这是JSONString我已经存储在我的项目中.

public class MainActivity extends Activity {
    MenuFields menuFieldInstance[];

    Gson gson = new Gson();

    String jsonObjectString = "{\n\n\n [\n \"id\": 22,\n \"menu_id\": 1,\n \"field_type_id\": 1,\n \"c4w_code\": \"1234\",\n \"field_label\": \"Customer No\",\n \"field_values\": \"\",\n \"date_Created\": \"2012-09-16 05:11:23\",\n \"date_modified\": \"2013-11-20 10:33:23\",\n \"is_required\": 0,\n \"is_static\": 1,\n \"field_order\": 1\n ],\n [\n \"id\": 23,\n \"menu_id\": 1,\n \"field_type_id\": 1,\n \"c4w_code\": \"1234\",\n \"field_label\": \"Company Name\",\n \"field_values\": \"\",\n \"date_Created\": \"2012-09-16 05:11:56\",\n \"date_modified\": \"2013-11-20 10:33:23\",\n \"is_required\": 1,\n \"is_static\": 1,\n \"field_order\": 3\n ]\n\n}";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main); …

我是android中的新手这里是JSON定义的,我需要在Android中使用JAVA手动将这个JSON存储在String变量中.我正在努力做到这一点.我尝试过的代码有些但是它不正确.

 String jsonObject = "{


        {
                      "id": 22,
                      "menu_id": 1,
                      "field_type_id": 1,
                      "c4w_code": "1234",
                      "field_label": "Customer No",
                      "field_values": "",
                      "date_Created": "2012-09-16 05:11:23",
                      "date_modified": "2013-11-20 10:33:23",
                      "is_required": 0,
                      "is_static": 1,
                      "field_order": 1
        },
        {
                      "id": 23,
                      "menu_id": 1,
                      "field_type_id": 1,
                      "c4w_code": "1234",
                      "field_label": "Company Name",
                      "field_values": "",
                      "date_Created": "2012-09-16 05:11:56",
                      "date_modified": "2013-11-20 10:33:23",
                      "is_required": 1,
                      "is_static": 1,
                      "field_order": 3
        }

}";

我需要将它存储在String或JSONObject中,以便我可以移动头来使用它.添加代码后:

MenuFields menuFieldInstance[];// an array of bean Class
Gson gson = new Gson();
 String jsonObjectString ="{\n\n\n {\n \"id\": 22,\n \"menu_id\": …