小编abh*_*hek的帖子

我有App A和App B.在App中我想向App B发送广播.这是App A的代码:

final Intent intent = new Intent();
intent.setAction("com.pkg.perform.Ruby");
intent.putExtra("KeyName", "code1id");
intent.setComponent(new ComponentName("com.pkg.AppB", "com.pkg.AppB.MainActivity"));
sendBroadcast(intent);

在App B - In中MainActivity,我有MyBroadCastReceiverClass.

public class MainActivity extends Activity {
    private MyBroadcastReceiver MyReceiver;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        // Receive broadcast from External App
        IntentFilter intentFilter = new IntentFilter("com.pkg.perform.Ruby");
        MyReceiver = new MyBroadcastReceiver();
        if(intentFilter != null)
        {
            registerReceiver(MyReceiver, intentFilter);
        }
    }

    public class MyBroadcastReceiver extends BroadcastReceiver
    {
        @Override
        public void onReceive(Context context, Intent intent) { …

我想使用扩展BackupAgentHelper的MyBackUpAgent类在Android中备份数据.我正在使用SharedPreferences来存储数据.

我的主要活动代码是:

public class MainActivity extends Activity {
    EditText inputtext; 
    TextView outputtext; 
    Button submit;   
    public static SharedPreferences sharedprefs;
    static final String File_Name_Of_Prefrences ="godplay_preferences";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main2);

        init();      
        sharedprefs=getSharedPreferences(File_Name_Of_Prefrences,MODE_PRIVATE);
        System.out.println("value="+sharedprefs.getString("Input",""));
        outputtext.setText(sharedprefs.getString("Input",""));


        submit.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub
                populateUI();
            }
        });
    }

    public void populateUI()
    {
        String savedinput=inputtext.getText().toString();
        System.out.println("savedinput="+savedinput);
        outputtext.setText(savedinput);
        sharedprefs=getSharedPreferences(File_Name_Of_Prefrences,MODE_PRIVATE);
        Editor editor=sharedprefs.edit();
        editor.putString("Input",inputtext.getText().toString());
        editor.commit();
        requestBackup();
    }

    private void init() throws ClassCastException
    {
        inputtext=(EditText) findViewById(R.id.edtInputText);
        outputtext=(TextView) findViewById(R.id.txtOutputText);
        submit=(Button) findViewById(R.id.btnSubmit); …

我有一个ImageView.当您单击ImageView时,它将打开图库,您将获取图像并在ImageView上显示它.我有一个条件,当我关闭我的应用程序,然后我打开它,图像将保留在那里.所以,为此,我将图像Uri存储在sharedprefrence上.在打开应用程序时,我正在检索相同的Uri并尝试在imageView上显示图像.

然而在一些手机中 - 图像看起来像Mi(Lollipop),三星(KitKat)一样完美,但它并没有出现在像摩托罗拉(Marshmallow),One Plus One(Marshmallow)这样的手机中.知道为什么会这样吗？这是我的代码

拿起我正在使用的图像

Intent intent=new Intent();intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent, "Select Picture"), Constants.SELECT_PICTURE);

在OnActivityResult()代码上

 @Override
 protected void onActivityResult(int requestCode, int resultCode, Intent data) {
     super.onActivityResult(requestCode, resultCode, data);

     if(requestCode==Constants.SELECT_PICTURE && resultCode==RESULT_OK && null!=data) {
         Uri uri=data.getData();
         Picasso.with(UsersProfileActivity.this)
             .load(uri)
             .centerCrop()
             .resize(200,200)
             .into(img_photo);

         // This profile image i am storing into a sharedpreference        
         profile_image=uri.toString();
     }

在从sharedprefrence检索时,我通过使用将String转换为uri Uri.parse(profile_image)

但是如果我注意到,uri为不同的Android手机返回如下

Mi(Lollipop)- Uri=content://media/external/images/media/12415
samsung(KitKat)-Uri=content://media/external/images/media/786
Motorola(Marshmallow)- Uri=content://com.android.providers.media.documents/document/image%3A30731
One Plus One (Marshmallow)- Uri=content://com.android.providers.media.documents/document/image%3A475

因此,当uri内容是-content:// media/external/images/media /是在ImageView Perfect上显示图像时,在其他情况下它不是

如何使graphview背景完全空白,甚至不显示x轴和y轴.在网上找不到任何东西

我正在尝试将listview项目制成带有圆角的矩形形状,但是我发生了什么,只有第一行在上部带有圆角,其余的子列表视图项目都是矩形,没有圆角.我不知道为什么会这样.

这是我的listview代码:

<ListView
    android:id="@+id/listViewdoctorwithappointment"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:layout_marginLeft="7dp"
    android:layout_marginRight="7dp"
    android:layout_marginTop="10dp"
    android:minHeight="80dp"
    android:background="@drawable/customshapeduplicate"
    android:cacheColorHint="@android:color/transparent"
    android:divider="#4F94CD"
    android:dividerHeight="10dp"

    android:smoothScrollbar="true"

    android:listSelector="@drawable/selector"
    android:scrollbars="none" >
</ListView>

这是我的customshapeduplicatefile是这样的:

<shape xmlns:android="http://schemas.android.com/apk/res/android" 
    android:shape="rectangle"> 
    <gradient android:startColor="#ffffff" android:endColor="#ffffff" 
        android:angle="270"/> 

    <corners android:bottomRightRadius="10dp" android:bottomLeftRadius="10dp" 
        android:topLeftRadius="10dp" android:topRightRadius="10dp"/> 
</shape> 

这是图像:

我有一个自定义列表视图,每行包含一个复选框和文本.现在我想要的是如果任何一个listview行的复选框被选中,那么其他行中的其他复选框如果被选中.it将被自动选择.(即一次只能选择一个复选框).我应该这样做.

到目前为止,我所做的工作如下:

public class CustomAdapter extends BaseAdapter{

    Context context;
    List<String> items;

     boolean array[];


    public CustomAdapter(Context context, List<String> items) {
    super();
    this.context = context;
    this.items = items;
    array =new boolean[items.size()];
}


    @Override
    public int getCount() {
        // TODO Auto-generated method stub
        return items.size();
    }

    @Override
    public Object getItem(int position) {
        // TODO Auto-generated method stub
        return items.get(position);
    }

    @Override
    public long getItemId(int position) {
        // TODO Auto-generated method stub
        return position;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) …

我有3项活动.活动A,活动B,活动C.这是流程A-> B-> C. 现在我想从C.(即C-> A)来到活动A,而没有得到活动A的onCreate().

到目前为止,我的代码是:但它将调用ActivityA的onCreate().我想调用Restart().

Intent intent=new Intent(ActivityC.this,ActivityA.class);
                intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
                startActivity(intent);
                finish();