我的webpack.config.js
var path = require("path")
var webpack = require('webpack')
var BundleTracker = require('webpack-bundle-tracker')
module.exports = {
context: __dirname,
entry: [
'webpack-dev-server/client?http://localhost:3000',
'webpack/hot/only-dev-server',
'./assets/js/index', // entry point of our app. assets/js/index.js should require other js modules and dependencies it needs
],
output: {
path: path.resolve('./assets/bundles/'),
filename: "[name]-[hash].js",
publicPath: 'http://localhost:3000/assets/bundles/', // Tell django to use this URL to load packages and not use STATIC_URL + bundle_name
},
plugins: [
new webpack.HotModuleReplacementPlugin(),
new webpack.NoEmitOnErrorsPlugin(), // don't reload if there is an error
new …Run Code Online (Sandbox Code Playgroud) 我正在使用django 1.7作为我的应用程序.我遇到了一些迁移问题.每当我尝试更改外键模型中的字段名称时,它就会中断.唯一的解决方法是去到数据库,并修复它,它们运行migrate之后syncdb.当我的应用程序变得更大时,我如何解决这些问题,并且随着我的架构更改,我将很快花费更多时间来解决数据库错误.django 1.7不支持South并且有自己的迁移功能并不强大?(我不确定,只是初学者)
当我使用 4 个文件时,所有文件都在选项卡(VIM)中打开。我想保存更改并编译它而不必关闭选项卡,即我想在新选项卡中打开一个终端以及现有的 4?
我应该如何在 VIM 中做到这一点?
我无法从PyCharm中访问Python文档.我试过了View | Quick Documentation,它说No Documentation Found.有没有简单的方法我可以配置它来显示文档?
为了澄清,我正在寻找Python文档,即内置库的功能/特性的描述,而不是有关PyCharm本身的文档.
无法让一个简单的你好世界工作!
server.js
var webpack = require('webpack')
var WebpackDevServer = require('webpack-dev-server')
var config = require('./webpack.config')
new WebpackDevServer(webpack(config), {
publicPath: config.output.publicPath,
hot: true,
inline: true,
historyApiFallback: true
}).listen(3000, '0.0.0.0', function (err, result) {
if (err) {
console.log(err)
}
console.log('Listening at 0.0.0.0:3000')
})
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webpack.config.js
var path = require("path")
var webpack = require('webpack')
var BundleTracker = require('webpack-bundle-tracker')
module.exports = {
context: __dirname,
entry: [
'./assets/js/index', // entry point of our app. assets/js/index.js should require other js modules and dependencies it needs
'webpack-dev-server/client?http://localhost:3000',
'webpack/hot/only-dev-server',
], …Run Code Online (Sandbox Code Playgroud) 我需要从多个表中获取列,我该如何实现?
UserLog
+------------+----------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------+----------+------+-----+---------+----------------+
| log_id | int(11) | NO | PRI | NULL | auto_increment |
| time | datetime | NO | | NULL | |
| ip_address | char(15) | YES | | NULL | |
| event_id | int(11) | NO | MUL | NULL | |
| user_id | int(11) | NO | MUL | NULL | |
+------------+----------+------+-----+---------+----------------+
Events
+-------------+--------------+------+-----+---------+----------------+
| …Run Code Online (Sandbox Code Playgroud) 与Java不同,在python中将模块导入另一个模块并调用模块的方法时,为什么主体中的代码会被执行而不是只执行方法中的代码?
示例(取自另一个SO问题):
def func():
print("func() in one.py")
print("top-level in one.py")
if __name__ == "__main__":
print("one.py is being run directly")
else:
print("one.py is being imported into another module")
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import one
print("top-level in two.py")
one.func()
if __name__ == "__main__":
print("two.py is being run directly")
else:
print("two.py is being imported into another module")
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当我运行这个:
python two.py
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我明白了:
top-level in one.py
one.py is being imported into another module
top-level in two.py
func() in one.py
two.py is being run directly
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如果我只想要执行的func()方法, …
我正在从数据库中检索数据并将其发送到json到前端.现在时间在UTC中存储为数据库,所以我想在将数据发送到前端之前更改时区及其格式.改变/转换前端的时间不是一种选择.
我该怎么办?
注意:我可以在模板中转换为适当的时区和格式.但是我现在想在视图中这样做.
def fetchinfo(request):
uid = int(request.user.id)
data = UserLog.objects.filter(user_id=uid).values('event_id__description','time','ip_address')
return JsonResponse({'status':'success','data':list(data),})
延迟语句推迟执行函数,直到周围的函数返回.但是,如果我尝试打印执行以下功能所花费的时间,它总是打印0.
func sum() {
start := time.Now()
//expecting to print non zero value but always gets 0
defer fmt.Println(time.Now().Sub(start))
sum := 0
for i := 1; i < 101; i++ {
sum += i
}
time.Sleep(1 * time.Second)
fmt.Println(sum)
}
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django ×3
reactjs ×2
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django-south ×1
django-views ×1
go ×1
pycharm ×1
python ×1
vim ×1